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kompoz [17]
3 years ago
7

I need help solving it

Mathematics
1 answer:
Oxana [17]3 years ago
6 0
7. the last one

I = P R T

I = 15.75 P = 500 R = unknown T = 6

15.75 = 500 (r) (6)

divide the T and I

15.75 ÷ 6 = 500 (r) (6) ÷6

2.62 = 500 (r) *get rid of the six*

divide the P with new answer

2.62 ÷ 500 = 500 ÷ 500 *get rid of 500*

0.00524 = r

move decimal to make it in to a percentage

5.24% = R






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What is 9/27 simplified
Vilka [71]
It's 1/3 which can = 0.3333...
7 0
4 years ago
Help xd <br> -(x+2) =<br> 3(7x - 8)=<br> 7(x+3)-5x<br><br> Thank you!
HACTEHA [7]

Answer:

x=−5

x= 31/21 =1 10/21= 1.476190476

2x+21

hope this helps

3 0
3 years ago
Read 2 more answers
Isaac is making sandwiches for a group of friends. He needs 3 ounces of meat for each sandwich.
lidiya [134]

Answer:

Part A: x=3

Part B: 6oz

3x=18

Step-by-step explanation:

Part A-

So, he needs 3 oz for each sandwich.

This gives us 3 for the equation.

The question says that we need an equation for this.

If we need an equation, we could write something like

x=3

There's really not anything else that we could write here.

Part B-

We now have something that we need to write.

He has 18 oz for sandwiches.

Each sandwich needs 3 oz.

So, we can write something like 3x=18

Then we could solve the equation by dividing both sides by 3.

This will leave us with x=6

Hope this works!

6 0
3 years ago
Read 2 more answers
Some kangaroos can cover 30 feet in a single jump if a kangaroo counts jump like that 150 times in a row how much farther wound
Svetradugi [14.3K]

Answer:

Distance farther the Kangaroos need to go to cover a mile = 780 feet

Step-by-step explanation:

Given:

Kangaroos cover 30 feet in a single jump.

Kangaroos can make such jumps 150 times in a row.

To find the distance farther it needs to go to cover a mile.

Solution:

Using unitary method to find distance covered by kangaroos in a row.

If in a single jump Kangaroos cover = 30 feet

So, in 150 jumps it will cover = 30\ ft \times 150 = 4500 feet

We know 1 mile = 5280 feet

Thus, distance farther the Kangaroo needs to go to cover a mile will be = 5280\ ft-4500\ ft = 780 feet

6 0
3 years ago
Please help i don't understand!
meriva

Step-by-step explanation:

you did not tell us what we need to create or find or calculate.

I guess from the picture this is one of the new methods to factoring equations. typically where the method is often more complicated than just thinking logically and doing it.

let's see if I can figure that one out.

but first, the basic, normal approach.

factoring the equation means that find in this case (as it is a quadratic equation) 2 terms in x in the form

(ax + b)(cx + d) = 10x² - x - 2

with a, b, c, d being integer values.

after doing the multiplications we get

acx² + bcx + adx + bd = 10x² - x - 2

acx² + (bc + ad)x + bd = 10x² - x - 2

we see

ac = 10

bc + ad = -1

bd = -2

10 can be factored as

10×1

-10×-1

5×2

-5×-2

-2 can be factored as

-1×2

1×-2

so, get -1 for the middle one, I am trying to get -5 + 4. and that is possible by saying

b = -1

c = 5

d = 2

a = 2

to check

ac = 2×5 = 10

bc + ad = -1×5 + 2×2 = -5 + 4 = -1

bd = -1×2 = -2

that works perfectly.

so the factoring is

(2x - 1)(5x + 2) = 10x - x - 2

now to the box method :

the general quadratic equation is

ax² + bx + c

that means for us

a = 10

b = -1

c = -2

the box square starts with

-2

10x²

now we find 2 numbers that multiply across to a×c = -20 and add together to b = -1

n×m = -20

n+m = -1

n = -1 - m

and that we use in the first equation

(-1 - m)×m = -20

-m² - m + 20 = 0

m² + m - 20 = 0

using the general solution for such quadratic equations

m = (-1 ± sqrt(1² - 4×1×-20))/(2×1) = (-1 ± sqrt(81))/2 =

= (-1 ± 9)/2

m1 = (-1 + 9)/2 = 8/2 = 4

m2 = (-1 - 9)/2 = -10/2 = -5

as we see (n×m = -20) m1 = n2 and m2 = n1

so, the 2 numbers (sequence irrelevant) are -5, 4.

they represent -5x and 4x. the negative one goes in the upper enough box.

-5x -2

10x² 4x

now we create a column to the left of the box table, and a row below the box table.

the left column gets the greatest common factor of the line elements.

the greatest common factor of -5x and -2 is -1.

the greatest common factor of 10x² and 4x is 2x.

-1 -5x -2

2x 10x² 4x

the bottom row divides the last row by the left column element

10x² / 2x = 5x

4x / 2x = 2

-1 -5x -2

2x 10x² 4x

5x 2

and the factorization is then the left column and the bottom row :

(2x - 1)(5x + 2)

now anybody tell me this is not much more complicated than the direct method.

this is only advisable, if the direct method has too many options to try and combine.

I hope I found the right thing your teacher wants here.

8 0
2 years ago
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