At x=0 y=6 the y intercept. The rate is -0.25 so the equation is y=6-0.25x. The ordered pair is (x,6-0.25x).
Answer:
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Step-by-step explanation:
Answer:
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Class 9
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>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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You would need the 3rd side length of the triangle, in order to find the area.
Answer:
(a)
x cubed is
=x^3=x3
5 times the cube of x is
=5x^3=5x3
4 times x is
=4x=4x
the quotient of 4 times x and 3 is
=\frac{4x}{3}=34x
so,
the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is
=5x^3-\frac{4x}{3}=5x3−34x ..........Answer
(b)
5 times cube of x is
=5x^3=5x3
5 times cube of x divided by 4 times x is
=\frac{5x^3}{4x}=4x5x3 ..........Answer
(c)
difference of 5 times x cube and 4 is
=5x^3 -4=5x3−4
so,
the quotient of the difference of 5 times x cube and 4 and x is
=\frac{5x^3-4}{x}=x5x3−4 ...........Answer
(d)
difference of 5 times x and 4 is
=5x-4=5x−4
so,
the cube of the difference of 5 times x and 4 is is
=(5x-4)^3=(5x−4)3 ............Answer