The solution for this problem is:
If there is 60 platters of B at a cost of $720:
(220 - 60 x 3) / 4 = 10 platters of A to make up for the deficit in hamburgers
(270 - 60 x 4) / 3 = 10 platters of A to make up for the deficit in hot dogs
(250 - 60 x 5) / 2 = 0 platters of A since there is no deficit in pigs feet
So 10 platters A are required at a cost of $150. $720 + $150 = for a total minimum cost of $870.
<h2>
Answer:</h2>
<u>The cost would be </u><u>$15.86</u>
<h2>
Step-by-step explanation:</h2>
The cost of 1 steak is $6.10
The cost of 2 3/5 steaks will be
Cost of 2 3/5 steaks = 6.10 * 2 3/5
Cost of 2 3/5 steaks = $15.86
Answer:
5*0.75= 3.75 he'll spend $3.75 on lunch every week.
Step-by-step explanation:
Answer:
Uncopyrightable
Step-by-step explanation: