The monthly income is $844.
Given:
- Weekly earning after taxes is $700
- Monthly rent is $725
- Monthly expense for utilities is $125
- Monthly expense for cable/internet is $120
- Monthly expense for cellphone is $35
- Monthly expense for bus fare is $48
- Minimum monthly payment of credit card debt is $78
- Monthly expense for groceries is $600
- Monthly expense for dining out and entertainment is $225
To find: The monthly income
The monthly income refers to the amount of money left over each month after paying all expenses.
Evaluating, we have,
The total monthly expense = $(
)
That is, the total monthly expense is $1956.
It is given that weekly earning after taxes is $700. Since a month contains 4 weeks, we can say that monthly earning after taxes is $(
), that is, $2800.
Then, monthly income is given by the difference between the monthly earnings and the monthly expenses. So, monthly income is $(
), that is, $844.
The monthly income is $844.
Learn more about income and expenses here:
brainly.com/question/18456246
Answer:
15 sec
Step-by-step explanation:
Data:
let m = 600 kg
b = 50
the differential equation will be:
Answer:
The Chinese act
Step-by-step explanation:
E^2=0.36 take the square root of both sides
e=±0.6
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
