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cluponka [151]
3 years ago
14

Help I need to bring this tomorrow

Mathematics
1 answer:
Karolina [17]3 years ago
4 0
I can't see it from here
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Courtney picked 7 quarts of blueberries. She wants to share them equally among 3 of her neighbors. What fractional part of the b
Brilliant_brown [7]

Answer:

7 / 1/3

Step-by-step explanation:

3 0
3 years ago
?????????help??????????
maxonik [38]
I hope it will work
6 = (0.08)w
6 0
3 years ago
Use the Distributive Property to expand 6(-4x + 3y).​
Anna11 [10]

Answer:

-24x + 18y

Step-by-step explanation:

6 x -4x = -24x

6 x 3y = 18y

7 0
3 years ago
Let T: P2 → P3 be the transformation that maps a polynomial p(t) into the polynomial (t-2)p(t).
lutik1710 [3]

(a) Applying <em>T</em> to <em>p(t)</em> = 2 - <em>t</em> + <em>t</em> ² gives

<em>T</em> ( <em>p(t)</em> ) = (<em>t</em> - 2) (2 - <em>t</em> + <em>t</em> ²) = -4 + 4<em>t</em> - 3<em>t</em> ² + <em>t</em> ³

(b) <em>T</em> is a linear transformation if for any <em>p(t)</em> and <em>q(t)</em> in <em>P</em>₂ and complex scalars <em>a</em> and <em>b</em>, the image of any linear combination of <em>p</em> and <em>q</em> is equal to the linear combination of the images of <em>p</em> and <em>q</em>. In other words,

<em>T</em> ( <em>a</em> <em>p(t)</em> + <em>b</em> <em>q(t)</em> ) = <em>a</em> <em>T</em> ( <em>p(t)</em> ) + <em>b</em> <em>T</em> ( <em>q(t)</em> )

Let

<em>p(t)</em> = <em>α</em>₀ + <em>α</em>₁ <em>t</em> + <em>α</em>₂ <em>t</em> ²

<em>q(t)</em> = <em>β</em>₀ + <em>β</em>₁ <em>t</em> + <em>β</em>₂ <em>t</em> ²

Compute the images of <em>p</em> and <em>q</em> :

<em>T</em> ( <em>p(t)</em> ) = (<em>t</em> - 2) (<em>α</em>₀ + <em>α</em>₁ <em>t</em> + <em>α</em>₂ <em>t</em> ²)

… = -2<em>α</em>₀ + (<em>α</em>₀ - 2<em>α</em>₁) <em>t</em> + (<em>α</em>₁ - 2<em>α</em>₂) <em>t</em> ² + <em>α</em>₂ <em>t</em> ³

Similarly,

<em>T</em> ( <em>q(t)</em> ) = -2<em>β</em>₀ + (<em>β</em>₀ - 2<em>β</em>₁) <em>t</em> + (<em>β</em>₁ - 2<em>β</em>₂) <em>t</em> ² + <em>β</em>₂ <em>t</em> ³

Then

<em>a</em> <em>T</em> ( <em>p(t)</em> ) + <em>b</em> <em>T</em> ( <em>q(t)</em> ) = <em>a</em> (-2<em>α</em>₀ + (<em>α</em>₀ - 2<em>α</em>₁) <em>t</em> + (<em>α</em>₁ - 2<em>α</em>₂) <em>t</em> ² + <em>α</em>₂ <em>t</em> ³) + <em>b</em> (-2<em>β</em>₀ + (<em>β</em>₀ - 2<em>β</em>₁) <em>t</em> + (<em>β</em>₁ - 2<em>β</em>₂) <em>t</em> ² + <em>β</em>₂ <em>t</em> ³)

… = <em>c</em>₀ + <em>c</em>₁ <em>t</em> + <em>c</em>₂ <em>t</em> ² + <em>c</em>₃ <em>t</em> ³

where

<em>c</em>₀ = -2 (<em>a</em> <em>α</em>₀ + <em>b</em> <em>β</em>₀)

<em>c</em>₁ = <em>a</em> (<em>α</em>₀ - 2<em>α</em>₁) + <em>b</em> (<em>β</em>₀ - 2<em>β</em>₁)

<em>c</em>₂ = <em>a</em> (<em>α</em>₁ - 2<em>α</em>₂) + <em>b</em> (<em>β</em>₁ - 2<em>β</em>₂)

<em>c</em>₃ = <em>a</em> <em>α</em>₂ + <em>b</em> <em>β</em>₂

Computing the image of <em>a</em> <em>p(t)</em> + <em>b</em> <em>q(t)</em> would give the same result; just multiply it by <em>t</em> - 2 and expand. This establishes that <em>T</em> is indeed linear.

(c) Find the image of each vector in the basis for <em>P</em>₂ :

<em>T</em> (1) = (<em>t</em> - 2) × 1 = <em>t</em> - 2

<em>T</em> (<em>t</em> ) = (<em>t</em> - 2) <em>t</em> = <em>t</em> ² - 2<em>t</em>

<em>T</em> (<em>t</em> ²) = (<em>t</em> - 2) <em>t</em> ² = <em>t</em> ³ - 2<em>t</em> ²

Then

T=\begin{bmatrix}-2&0&0\\1&-2&0\\0&1&-2\\0&0&1\end{bmatrix}

4 0
3 years ago
Using all the letters in the alphabet how many two letter codes can we form if we are allowed to use the same letter twice?
babymother [125]
There are 26 possible choices for the 1st letter in the code.
There are also 26 choices for the 2nd letter in the code.

---> 26*26 = 676 total possible two-letter codes
4 0
3 years ago
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