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Olin [163]
2 years ago
12

In the equation above k is a constant if y = 2 when x= 5 what is the value of x when y= 5

Mathematics
1 answer:
Tresset [83]2 years ago
6 0

The value f x when y= 5 is 2

<h3>Variations </h3>

Let the given equation be y = k/x

where k is the constant

if y = 2 when x= 5, then;

k = xy

k= 2(5)

k = 10

In order to determine the value of x when y = 5

x = k/y

x = 10/5

x = 2

Hence the value f x when y= 5 is 2

Learn more on variation here: brainly.com/question/6499629

#SPJ1

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21x <br> 3<br> +28x <br> 2<br> −49x−12x <br> 2<br> −16x+28
Serhud [2]

Answer:

2

1

3

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8

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4

9

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1

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8 0
3 years ago
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melisa1 [442]

Answer:

D. 18.68

Step-by-step explanation:

27\div \frac{5}{3}-6+53\times (\frac{2}{5})^2

Applying PEMDAS as order of operations.

Solving the exponents first [(\frac{2}{5})^2=\frac{4}{25}]

=27\div \frac{5}{3}-6+53\times \frac{4}{25}

Multiplying [53\times \frac{4}{25}=8.48]

=27\div \frac{5}{3}-6+8.48

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