Answer:
$1.50
Step-by-step explanation:
To find the best deal, we first want to consider price per unit. To find the price per unit, we divide the price by the number of units. For the 10 shin guard package, our price is 14.50, and we divide that by 10 to get 1.45 . Therefore, our unit price for the package of 10 is $1.45 per shin guard. Similarly, we can find the unit price for the package of 15 to be 22.5/15 = $1.50 per shin guard. As 1.50 is greater than 1.45, the lowest unit price is for the package of 10.
The question is asking for us to compare the prices if we bought 30 of each. For the package of 10, we get 1.45*30 (as we're buying 30 for 1.45) = 43.5 as the total price, and for the package of 15, we get 1.5*30 = 45 as our price. As 15 and 10 are both factors of 30, we don't need to worry about converting it back into packages of 10/15. The difference between buying 30 at the lowest and highest unit price is therefore (45-43.5)=1.5 dollars
Answer:
3.43
Step-by-step explanation:
To do this you would first find the area of the square which is 16. Then you would find the area of the 2 semicircle or just on whole circle. We are just going to use the formula for a whole circle since there are 2 semicircles. The formula to find a circle is pi times r^2 so we are going to put that into a calculator so we would do pi times 2 (radius of circle)^2 which is 12.57 and we would subtract 16 by 12.57 which is 3.43
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer: 9 associate property 8 commutative property
Step-by-step explanation:
