There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
That's an expression, so the only thing you can do is simplify it, but that already looks simplified.
Answer:
okay so,
so do a 16 by 14 rectangle it should be good
sry if its wrong i tried but i hope it helped ;0
Answer:
m = 35
Step-by-step explanation:
2m + m -15 = 90
3m -15 = 90
+15 +15
3m = 105
/3 /3
m = 35
To check the work just insert 35 for m:
2(35) + 35 -15 = 90
70 + 35 -15 = 90
105 - 15 = 90
90 = 90
