Question

I BEG YOU I WILL DO ANYTHING HELP algebraically solve the following system of equations. Show all your work

Answer 1

Answers:

• Solving for x on the question - 2x + 3y = 32  |  

1. Answer : x =  $\frac{-3}{2}$⁻y + 16

• Solving for y on the question - 2x + 3y = 32  |  

1. Answer : y = $\frac{-2}{3}$x + $\frac{32}{3}$

• Solving for x on question - 5x - 4y = -81 |

1. Answer : x =  $\frac{4}{5}$y + $\frac{-81}{5}$

• Solving for y on question - 5x - 4y = -81 |

1. Answer : y =  $\frac{-5}{4}$x + $\frac{81}{4}$

Step-by-step explanation:

(Solving for x on question - 2x + 3y = 32)

2x + 3y = 32

Step 1: Add -3y to both sides.

2x + 3y + −3y = 32 + −3y

2x = −3y + 32

Step 2: Divide both sides by 2.

$\frac{2x}{2}$  = $\frac{-3y+32}{2}$

x =  $\frac{-3}{2}$⁻y + 16                                                                                                                

(Solving for y on question - 2x + 3y = 32)

2x + 3y = 32

Step 1: Add -2x to both sides.

2x + 3y + −2x = 32+ −2x

3y = −2x + 32

Step 2: Divide both sides by 3.

$\frac{3y}{3}$ =  $\frac{-2x+32}{3}$

y = $\frac{-2}{3}$x + $\frac{32}{3}$                                                                                                          

(Solving for x on question - 5x - 4y = -81)

5x − 4y = −81

Step 1: Add 4y to both sides.

5x − 4y + 4y = −81 + 4y

5x = 4y − 81

Step 2: Divide both sides by 5.

$\frac{5x}{5}$ =  $\frac{4y-81}{5}$

x =  $\frac{4}{5}$y + $\frac{-81}{5}$                                                                                                              

(Solving for y on question - 5x - 4y = -81 )

5x − 4y = −81

Step 1: Add -5x to both sides.

5x − 4y + −5x = −81 + −5x

−4y = −5x − 81

Step 2: Divide both sides by -4.

$\frac{-4y}{-4}$ = $\frac{-5x-81}{-4}$

y =  $\frac{-5}{4}$x + $\frac{81}{4}$