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kirza4 [7]
3 years ago
9

What is the equation of this line of best fit in slope-intercept form?

Mathematics
1 answer:
Harman [31]3 years ago
7 0
The correct answer is y=1/2x+1
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Express each ratio as a fraction in lowest terms.
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Just write the first number as the numerator and the second one as a denominator then divide by their common factors
6 0
3 years ago
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
What are the possible values of x in x2 + 3x + 3 = 0?
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x^2+3x+3=0\\&#10;&#10;\Delta=9-4*3=-3\\&#10;&#10;x= \dfrac{-3-i*\sqrt{3}}{2} \ or\ x= \dfrac{-3+i*\sqrt{3}}{2} \\&#10;&#10;
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WILL GIVE BRAINLIST AS SOON AS I CAN i thought that this one was 151.45 but it wasn't and I'm not sure what to do ​
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151.4496

Step-by-step explanation:

Take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2

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You have a solid Rectangle of dough. Consider the cross sections that are formed when you slice into the cube as described. Draw
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B is the answer I think trying it tho
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