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2 years ago

8

Which of the following is needed to construct a hexagon?

2 answers:

amid [387]2 years ago

8 0

Answer:

The correct answer is six equilateral triangles.

Step-by-step explanation:

The angle at the center of the hexagon is 360°, which is being divided into 6 equal parts. The value of each angle at the center is equal to 60°. All three angles of the 6 triangles formed in the given hexagon are equal to 60°. This proves that there are 6 equilateral triangles.

Nadusha1986 [10]2 years ago

7 0

The answer choice which represents the what is needed to construct a hexagon is Choice B; Six isosceles triangles.

What is needed to construct a hexagon?

By definition, an hexagon is a closed figure with six equal sides and six congruent interior angles.

On this note, upon assembly of six isosceles triangle s in which cases, the excluded side of the isosceles triangles form the sides of the hexagon and the congruent sides represents lines joining each vertex to the center of the hexagon, an hexagon is formed.

Read more on hexagon;

brainly.com/question/1615720

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peter buys 8.5 square feet of carpet. the carpet cost $10.20 cents per square foot. how much does peter pay for the carpet?

Fiesta28 [93]

10.20*8= 81.60
10.20*.5= 5.10
add
81.60+5.10= 86.70
ANSWER: Peter pays $86.70 for the carpet

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3 years ago

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

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2 years ago

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NikAS [45]

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3 years ago

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Arlecino [84]

Step-by-step explanation:

Collinear points have the same gradient

find the gradient(slope) between AB first

$= \frac{1 - 2}{3 - 1} \\ = \frac{ - 1}{2}$

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2 years ago

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kolbaska11 [484]

Hello!

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3 years ago

Read 2 more answers