The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
1.)-2
2)-2
3.)-3
4.)-1
5)1
6.)-6
7.)-6
8.)4
9.)0
10.)no solution
11.)-3
12.)all real numbers
13.)-1
14.)5
On working on the work for the first problem so u understand
967.50 = 450 + 28.75p
967.50 - 450 = 28.75p
517.5 = 28.75p
18 = p
90 mins + 50 mins = 140 mins
60 mins ==1 hr 2*60 = 120 mins
140 mins -120 mins= 20 mins
2 hrs ans 20 mins is the answer
