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Gre4nikov [31]
2 years ago
8

Which of the following is needed to construct a hexagon?

Mathematics
2 answers:
amid [387]2 years ago
8 0

Answer:

The correct answer is six equilateral triangles.

Step-by-step explanation:

The angle at the center of the hexagon is 360°, which is being divided into 6 equal parts. The value of each angle at the center is equal to 60°. All three angles of the 6 triangles formed in the given hexagon are equal to 60°. This proves that there are 6 equilateral triangles.

Nadusha1986 [10]2 years ago
7 0

The answer choice which represents the what is needed to construct a hexagon is Choice B; Six isosceles triangles.

What is needed to construct a hexagon?

By definition, an hexagon is a closed figure with six equal sides and six congruent interior angles.

On this note, upon assembly of six isosceles triangle s in which cases, the excluded side of the isosceles triangles form the sides of the hexagon and the congruent sides represents lines joining each vertex to the center of the hexagon, an hexagon is formed.

Read more on hexagon;

brainly.com/question/1615720

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Evaluate abc² if a= -3, b= 6, and c= -8​
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Answer:

-1152

Step-by-step explanation:

abc² the expression can be rewritten using the given values for each letter

(-3)*6*(-8)^2 now we find the second power of (-8) by multiplying it with itself

(-8)*(-8) = 64

(-3)*6*64 = -1152

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3 years ago
What is the slope of the line that passes through the points (-10, -8) and (−8,−16)? Write your answer in simplest form.
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Answer:y=-8 x=2

-8/2 or -4

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
the pressure, P, of a gas varies inversely with its volume, V. pressure is measured in units of PA. Suppose that a particular am
miss Akunina [59]

The pressure is 39 Pa if the volume is expanded to 168L and the pressure, P, of a gas varies inversely with its volume, V.

<h3>What is a proportional relationship?</h3>

It is defined as the relationship between two variables when the first variable increases, the second variable also increases according to the constant factor.

We have:

The pressure, P, of a gas varies inversely with its volume, V.

P ∝ 1/V

P = k/V

k is the constant.

If P = 126 Pa and V = 52 L

126 = k/52

k = 6552

P = 6552/V

Plug V = 168 L

P = 6552/168 = 39 Pa

Thus, the pressure is 39 Pa if the volume is expanded to 168L and the pressure, P, of a gas varies inversely with its volume, V.

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