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Sloan [31]
3 years ago
10

If the expression ax(2x + y - 5) simplifies to 6x² +3xy - 15x, what is the value of a?

Mathematics
2 answers:
nata0808 [166]3 years ago
3 0
Since:
ax(2x + y - 5) = 6x^2 +3xy - 15x,

we should factor X out of the second equation to find out the value of a:
6x^2 + 3xy - 15x =
x(6x + 3y - 15),

Now that we factored X out, to find a, we need to find the other common factor:

(6x + 3y - 15) / (2x + y - 5),

which is 3.

Hence the value of a is 3
Liono4ka [1.6K]3 years ago
3 0

Answer:

a=3

Step-by-step explanation:

If ax(2x + y - 5) simplifies to 6x² +3xy - 15x

ax(2x + y - 5)=2ax^2+axy-5ax

Comparing Coefficients of 2ax^2+axy-5ax with 6x^2 +3xy - 15x

For x^2; 2a=6===>a=3

     xy: a=3

     x: -5a=-15==>a=3

Clearly, a=3

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Answer: 26.47%

Step-by-step explanation:

Given the following :

markup based on cost = 36%

Assume a cost of $50

$50 × 1.36 = $68

Now, markup based on the selling price ;

$68 - $50 = $18

Therefore, ratio of cost price to selling price :

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3 years ago
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
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Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
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Step-by-step explanation:

x+13÷2×2=4×2

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x=8-13

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