If the expression ax(2x + y - 5) simplifies to 6x² +3xy - 15x, what is the value of a?

2 answers:

3 0

Since:
ax(2x + y - 5) = 6x^2 +3xy - 15x,

we should factor X out of the second equation to find out the value of a:
6x^2 + 3xy - 15x =
x(6x + 3y - 15),

Now that we factored X out, to find a, we need to find the other common factor:

(6x + 3y - 15) / (2x + y - 5),

which is 3.

Hence the value of a is 3

Liono4ka [1.6K]2 years ago

3 0

Answer:

a=3

Step-by-step explanation:

If ax(2x + y - 5) simplifies to 6x² +3xy - 15x

$ax(2x + y - 5)=2ax^2+axy-5ax$

Comparing Coefficients of $2ax^2+axy-5ax$ with $6x^2 +3xy - 15x$

For $x^2;$ 2a=6===>a=3

xy: a=3

x: -5a=-15==>a=3

Clearly, a=3

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