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Andre45 [30]
4 years ago
6

Simplify the following expression. 33.414 - 33.36

Mathematics
2 answers:
Neporo4naja [7]4 years ago
7 0

Answer:

.054

Step-by-step explanation:

33.414 - 33.36 = .054

jeyben [28]4 years ago
6 0

Answer:

Step-by-step explanation:

33.414−33.36

=33.414−33.36

=33.414+−33.36

=0.054

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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
William is saving up to buy a new phone. He already has $23 and can save
Ipatiy [6.2K]

Step-by-step explanation:

current Amount of money 23

8x10=80

80+23=103

William will have 103$ after 10 weeks

4 0
3 years ago
PLEASE HELP
Kipish [7]

Answer:

yes tax is .7 per dollar there for every dollar u spend u pay an extra .7

3 0
3 years ago
A line passes through the point (-4,6) and has a slope of 5/4
kondaur [170]

Answer:

4y-5x-44=0

Step-by-step explanation:

It passes through one point with the formula being

y-y1=m(x-x1)

y-6=5/4(x-(-4))

y-6=5/4(x+4)

cross multiply

4(y-6)=5(x+4)

4y-24=5x+20

collect like terms

4y-5x=20+24

4y-5x=44

4y-5x-44=0

5 0
3 years ago
Read 2 more answers
Help ASAP with the question.
givi [52]
The answer is 5 x 10^10

Hope this helped!  :)
6 0
3 years ago
Read 2 more answers
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