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ivann1987 [24]
3 years ago
15

Consider the equation: x^2 = - 8x - 7​

Mathematics
2 answers:
Airida [17]3 years ago
6 0

Answer: The expression is not factorable with rational numbers.

Step-by-step explanation:

Natasha2012 [34]3 years ago
3 0

Answer:

0

Step-by-step explanation:

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Which ratio is equivalent to the ratio 33:36
xenn [34]

Answer:

Step-by-step explanation:

33/3 = 11

36/3 =13

11 :13

5 0
4 years ago
The sum of the digits of a 5 digit positive integer =2 how many five digits integers exist?
yaroslaw [1]
Answer- 90000/2=45000

5 0
3 years ago
Need these 2 answered. 25 points!<br><br> Please show work, Thanks! :)
sasho [114]
Hello!

1. -4x2 + 8x + 32
-4(x2 - 2x - 8)
-4(x2 + 2x - 4x - 8)
-4(x(x + 2) - 4(x + 2))
-4(x + 2)(x - 4)
Answer A.

2. 2x2 + 16x + 30
2(x2 + 8x + 15)
2(x2 + 5x + 3x + 15)
2(x(x + 5) + 3(x + 5))
2(x + 5)(x + 3)
Answer C.

3 0
3 years ago
Read 2 more answers
If f(x) = -x + 4 and g(x) = x^2 - 5, then g(f(3)) = ?<br> A) -8 <br> B) -4 <br> C) -3 <br> D) 0
kenny6666 [7]

Answer:

B) -4

Step-by-step explanation:

To solve g(f(3)), we first have to solve f(3):

Since f(x) = -x +4 , f(3) = -3 + 4 = 1

Now we have to solve g(1) , since that is what f(3) left us;

Since g(x) = x^2 - 5 , g(1) = 1^2 - 5 = 1 - 5 = -4

4 0
4 years ago
Kala’s company makes solid metal balls for various industrial uses. A customer wants aluminum balls that have a diameter of 6 in
KiRa [710]

7,912.8 inch³ of aluminum is needed to make 70 metal balls.

Step-by-step explanation:

Step 1:

The area of a sphere is calculated by multiplying \frac{4}{3} with π and the cube of the radius (r³).

In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.

The volume of a sphere,V = \frac{4}{3} \pi r^{3} .

So if r = 3 inches and π = 3.14,  

V = \frac{4}{3} (3.14) (3^{3})  = 113.04 cubic inches.

So for a single aluminum ball, 113.04 inch³ of aluminum is needed.

Step 2:

If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.

The aluminum needed for 70 metal balls = 70(113.04) = 7,912.8 inch³.

So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.

7 0
4 years ago
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