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bonufazy [111]
2 years ago
15

Which of the following is the correct factorization of the polynomial below x3 - 12

Mathematics
1 answer:
padilas [110]2 years ago
8 0

Answer:this is all I could find

Step-by-step explanation:

You might be interested in
(Literal equations) The formula for the volume of a cylinder is V = πr^2h. Solve V = πr^2h for h, the height of the cylinder. A.
Kobotan [32]

Answer:

C

Step-by-step explanation:

Given

V = πr²h

Isolate h by dividing both sides by πr²

\frac{V}{\pi r^2} = h → C

8 0
3 years ago
I need help plz<br> ASA <br> SSA <br> SAS<br> AAS
Lera25 [3.4K]

Answer:

SAS,

Step-by-step explanation:

2 sides and the included angle.

4 0
2 years ago
The Montanez family is a family of four people. They have used 3,485.78 gallons of water so far this month. They cannot exceed 7
il63 [147K]

Answer:

x ≤ 3764.72

Step-by-step expl anation:

The Montanez family cannot use more than 7250.50 gallons, this means that they can use less than or equal to 7250.50 gallons, this tells you which sign to use.  The variable x can be used to describe how much water they have left to use and then you add 3,485.78 gallons to x.

x + 3485.78 ≤ 7250.50   This inequality means that the amount of water the family has yet to use added to 3485.78 gallons cannot exceed 7250.50 gallons.

Next, you simplify the inequality using the property of inequalities.

x ≤ 7250.50 - 3485.78

x ≤ 3764.72

5 0
3 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
3 years ago
Find the value of h(-67) for the function below<br> h(x)=-49x-125
inessss [21]
Answer:
h(-67) = 3158
General Formulas and Concepts:
Order of Operations: BPEMDAS
- Substitution and Evaluation
Step-by-Step Explanation:
Step 1: Define
h(x) = -49x - 125
h(-67)

Step 2: Solve
1. Substitute: h(-67) = -49(-67) - 125
2. Multiply: h(-67) = 3283 - 125
3. Subtract: h(-67) = 3158
6 0
3 years ago
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