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1 year ago

Help ASAP!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

erica [24]1 year ago

7 0

Step-by-step explanation:

ATTACHED IS THE SOLUTION

Fittoniya [83]1 year ago

5 0

The answer would be +3 since ur adding 3 every time

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RADIOS is a hexagon that has six equal sides. The coordinates of side AD are (–4, 2) and (7, 2). What is the perimeter of the he

aev [14]

On desmos, a graphing calculator, I inputted your numbers, and I got that each side is 11 units long. Therefore, because a hexagon has 6 sides, you would have 6 * 11 = 66 units.

Therefore, your answer is 66.

Hope this helps and have a nice day:)

4 0

3 years ago

Read 2 more answers

If f(x) = 3x + 10 and g(x) = 2x - 4, find (f- g)(x).

densk [106]

Answer:

Step-by-step explanation:

<u>Operations with Functions</u>

Given two functions f(x) and g(x), the following operations are defined:

(f+g)(x)=f(x)+g(x)

(f-g)(x)=f(x)-g(x)

(f*g)(x)=f(x)*g(x)

(f/g)(x)=f(x)/g(x)

We have f(x)=3x+10 and g(x)=2x-4. Use the second formula to find

(f-g)(x)=(3x+10)-(2x-4)

Operating:

(f-g)(x)=3x+10-2x+4

Joining like terms:

(f-g)(x)=x+14

5 0

3 years ago

X=y-1 y=(4-2x) solve by substition

Nataliya [291]

Since you have an equation equal to both x and y, you can either substitute the equation equal to x for x or the equation equal to y for y.
x=y-1
y=4-2x
I would substitute the y in using 4-2x
x=(4-2x)-1
x=3-2x
3x=3
x=1
Then plug in x and solve for y
1=y-1
2=y

5 0

2 years ago

How do you do this question?

Sergeeva-Olga [200]

Answer:

V = 2000r³/3

Step-by-step explanation:

We know that the base is a circular disk, so it creates a circle on the xy plane. It would be in the form x² + y² = r². In other words x² + y² = (5r)². Let's isolate y in this equation now:

x² + y² = (5r)²,

x² + y² = 25r²,

y² = 25r² - x²,

y = √25r² - x² ---- (1)

Now remember that parallel cross sections perpendicular to the base are squares. Therefore Area = length^2. The length will then be = 2√25r² - x² --- (2). Now we can evaluate the integral from -5r to 5r, of [ 2√25r² - x² ]² dx.

$\int _{-5r}^{5r}\:\left[\:2\sqrt{\left(25r^2\:-\:x^2\right)}\:\right]\:^2\:dx\\=\int _{-5r}^{5r}4\left(25r^2-x^2\right)dx\\\\= 4\cdot \int _{-5r}^{5r}25r^2-x^2dx\\\\= 4\left(\int _{-5r}^{5r}25r^2dx-\int _{-5r}^{5r}x^2dx\right)\\\\= 4\left(250r^3-\frac{250r^3}{3}\right)\\\\= 4\cdot \frac{500r^3}{3}\\\\= \frac{2000r^3}{3}$

As you can see, your exact solution would be, V = 2000r³/3. Hope that helps!

3 0

2 years ago

What is the image point of (-3,3) after the transformation R180° 0 T-3, -4?

ZanzabumX [31]

Answer:

Image point → (6, 1)

Step-by-step explanation:

Given point → (-3, 3)

Transformation to be done → $R_{180}0T_{-3,-4}$

Transformations to be done,

Step - (1). Translation of the given by 3 units left and 4 units down.

Step - (2). Followed by the rotation counterclockwise 180° about the origin.

Rule for step (1),

(x, y) → (x - 3, y - 4)

By this rule,

(-3, 3) → [(-3 - 3), (3 - 4)]

→ (-6, -1)

Rule for step -2,

(x, y) → (-x, -y)

(-6, -1) → (6, 1)

Therefore, following these two steps coordinates of the image point → (6, 1)

6 0

2 years ago