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3 years ago

12

Jeremy plays basketball. He scored a total of 1489 points consisting of 2-point and 3-point baskets. If he made 640 baskets, how

many were 3-pointers?

1 answer:

pogonyaev3 years ago

3 0

213
3 pointers
because you divide the baskets by three and once you do that you will get your aswear of 213 3 pointers

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If the two lines y1 = -1/2x +5 and y2 = 2x + 5 were to be graphed, what would their intersection point represent?

grigory [225]

Answer:

D. Their intersection point is the only point where the same input into both functions yields the same output.

Step-by-step explanation:

The intersection point of 2 graphed lines represents the solution.

At this point, for both lines, there is the same x value (input) and the same y value (output) because both of the lines have that point in common.

So, if those 2 lines were to be graphed, the intersection point would represent the only point with the same input and output for both functions.

D is the correct answer.

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You roll 2 dice what is the probability that the sum of the dice is greater than 8 and that one die shows a six

MAXImum [283]

It'll be rare to do it

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3 years ago

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

kramer

Answer:

(a)

$\bar x = 0.0075$

$s = 0.0049$

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

$n = 8$

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}$

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 &{|1 - 2|} &0.003 & 0.015 & 0.006 & 0.004 & 0.002 & 0.010 & 0.005 & 0.015 \ \end{array}$

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}$

$\bar x = \frac{0.06}{8}$

$\bar x = 0.0075$

Next, calculate the standard deviation (s).

This is calculated using:

$s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}$

So, we have

$s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}$ $s = \sqrt\frac{0.00019}{8}$

$s = \sqrt{0.00002375$

$s = 0.0049$

Solving (b):

Of the given options (A - E), option B is correct because the sample is actually too small

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3 years ago

Have you ever been on or seen a ride like this at a fair or amusement park? Imagine being strapped into your seat at the bottom

Montano1993 [528]

Answer:

no

Step-by-step explanation:

The only question here seems to be ...

Have you ever been on or seen a ride like this at a fair or amusement park?

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I have not seen such a ride.

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valkas [14]

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( \cfrac{27}{8} \right)^{\frac{4}{3}}\implies \left( \cfrac{3^3}{2^3} \right)^{\frac{4}{3}}\implies \left( \cfrac{3^{3\cdot \frac{4}{3}}}{2^{3\cdot \frac{4}{3}}} \right)\implies \cfrac{3^4}{2^4}\implies \cfrac{81}{16}$

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3 years ago