Price of one adult ticket is $9 and price of one student ticket is also $9.
Step-by-step explanation:
Let,
Adult ticket = x
Student ticket = y
According to given statement;
x+2y=27 Eqn 1
2x+2y=36 Eqn 2
Subtracting Eqn 1 from Eqn 2;

Putting x=9 in Eqn 1;

Dividing both sides by 2;

Price of one adult ticket is $9 and price of one student ticket is also $9.
Keywords: linear equations, subtraction
Learn more about linear equations at:
#LearnwithBrainly
Let x = adult tickets
Let y = children's tickets
x + y = 800
8x + 4y = 4,400
From the first eq, x = 800 - y, plug this in to the second eq
8(800-y) + 4y = 4,400
6400 - 8y + 4y = 4,400
2000 = 4y
500 = y
x = 800 - 500
x = 300
300 adult tickets were sold.
Answer:
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Step-by-step explanation:
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Distribute negative sign.
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Combine like terms.
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
7x = -36+10x
X=12
You minus the 10 from 7 (7-10=-3) (-36/-3) gives you 12
Answer:
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Step-by-step explanation:
