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Vilka [71]
2 years ago
6

f the coordinates of point A are (8 , 0) and the coordinates of point B are (3 , 7), the y-intercept of is . If the coordinates

of point D are (5 , 5), the equation of line is y = x + .
Mathematics
1 answer:
Doss [256]2 years ago
8 0

The equation of the line is y = -7/5x + 56/5

<h3>Equation of a line</h3>

The formula for expressing equation of a line is given as y = mx + b

where

m is the slope

b is the y-intercept

Given the coordinates A(8, 0) and (3, 7)

Determine the slope

Slope =7-0/3-8

Slope = -7/5

For the intercept

0 = -7/5(8) + b

b = 56/5

Hence the equation of the line is y = -7/5x + 56/5

Learn more on equation of a line here:brainly.com/question/22119282

#SPJ1

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Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
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The typical full-time employee in a particular hotel works a 40-hour week. Last month, the hotel's 80 employees worked a total o
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Answer: There are 25 FTEs.

Step-by-step explanation:

Since we have given that

Number of hour week for full time employee = 40 hours

In a month we know that

Number of weeks = 4

Total number of hours in a month would be

40\times 4\\\\=160\ hours

If in last month, the hotel's 80 employees worked a total of 4000 hours,

So, Full time equivalent workers were employed by the hotel last month would be

\dfrac{4000}{160}\\\\=25

Hence, there are 25 FTEs.

7 0
3 years ago
When this 3-digit number is rounded to the nearest hundred, it rounds to 200.  Rounded to the nearest ten, this number rounds to
alisha [4.7K]
199, it rounds to 200 because it's closer to 200 than 100. It is also closer to 200 than to 190. And finally, 1 + 9 + 9 = 19
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Sally has three times as many dimes as nickels and twice as many quarters as dimes. In all she has $5.55.How many of each type o
OLEGan [10]
Sally has 3 nickels, 9 dimes, and 18 quarters
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3 years ago
Read 2 more answers
A rectangular rug has an area of 1 4/5 square yards. The width of the rug is 1 1/2 yards. What is the length,in yards,of the rug
vichka [17]

Answer:

1.2

Step-by-step explanation:

If you multiply the length by the width to find area, then you can divide the area by the width to find the length.


1\frac{4}{5} ÷ 1\frac{1}{2} = 1.2

7 0
3 years ago
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