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Bingel [31]
2 years ago
8

1/4x+5/3x-4=2-1/12x what is the answer ??????

Mathematics
2 answers:
IceJOKER [234]2 years ago
5 0
I hope this helps
the answer is x=3
alex41 [277]2 years ago
3 0
I believe the answer is: 

x=3

have a noice day
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A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The pr
____ [38]
It would be D. 5/20 because the other 2 you would add then subtract and then you would just put the answer yo get from subtracting it over 20. 

8 0
2 years ago
Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

3 0
1 year ago
Read 2 more answers
Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
2 years ago
X+y=10 and 2x+4y=30<br>What are the steps to solve this equation?
Ronch [10]

Answer:

x=5 and y=5

Step-by-step explanation:

You "plug" one equation into the other, to get a new equation that only has one variable (x or y), then you can simplify that and have your answer.

So let's plug the first into the second:

First, we convert the first equation into an x=... form. For this one, this means moving the +y to the other side:

x = 10 - y

Now we substitute 10-y for x in the second equation:

So 2x+4y=30 becomes:

2(10-y) + 4y = 30

And simplify that:

20 - 2y + 4y = 30

20 + 2y = 30

2y = 30-20

2y = 10

y = 5

This is the first answer! If we put this into the first equation, we get:

x = 10 - 5 = 5

Now we have both answers, x=5 and y=5

6 0
2 years ago
Find the area and please show the steps and explain. Thanks!
Anit [1.1K]
I'm pretty sure you just add all the numbers up so it would be 569.9 ft 
3 0
2 years ago
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