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SSSSS [86.1K]
2 years ago
8

Triangle QRS is to be dilated using the rule D Subscript P, three-fourths.

Mathematics
1 answer:
horrorfan [7]2 years ago
4 0

The distance from the center of dilation, P, to.the image vertice S' is; 6 units.

<h3>What is the distance from the center of dilation, P, to the image S'?</h3>

It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.

Ultimately, since the dilation factor is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6 units.

Read more on dilation;

brainly.com/question/10253650

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A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est
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Answer:

Point estimate for the population variance = 3.92 * 10^{-3} .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

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      1.13            1.13 - 1.188 = -0.058                                 3.364 * 10^{-3}

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      1.24           1.24 - 1.188 = 0.052                                 2.704 * 10^{-3}

      1.27           1.27 - 1.188 = 0.082                               <u>  6.724 * </u>10^{-3}<u>    </u>

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Firstly, Mean of above data, Xbar = \frac{\sum X}{n} = \frac{1.15+1.24+1.15+1.27+1.13}{5} = 1.188

Point estimate of Population Variance = Sample variance

                                                               = \frac{\sum (X-Xbar)^{2}}{n-1} = \frac{0.01568}{4} = 3.92 * 10^{-3} .

Therefore, point estimate for the population variance = 3.92 * 10^{-3} .

       

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