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Naya [18.7K]
2 years ago
9

Sketch the region that is common to the graphs of x ≥ 2,

Mathematics
1 answer:
Oliga [24]2 years ago
6 0

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

#SPJ1

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Https://docs.goo gle.com/forms/d/e/1FAIpQLSe6vil7bUd47FA8fnqS5sh23ZjJ1OUe5X2ZlogwND9MoURn0w/viewform?usp=sf_link
Galina-37 [17]

Answer:

uh.... Why??

Step-by-step explanation:

3 0
3 years ago
Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
kompoz [17]
Answer:

Magnitude: 121.35 pounds

Direction: 21.64°

Explanation:

1) Decompose each force into its x - y components.

2) Force 1, F1: 140 pounds at angle of 30°

x-component: F1,x

F1, x = F1 *cos(30°) = 140 pounds * cos(30°) = 121.24 pounds

y-component: F1,y

F1,y = F1 * sin(30°) = 140 pounds * sin(30°) = 70 pounds.

3) Force 2, F2: 75 poounds at 150°

x-component: F2,x

F2,x = F2 * cos(150°) = 75 pounds * cos(150°) = - 64.95 pounds

y-component: F2,y

F2,y = F2 * sin(150°) = 75 pounds * sin(150°) = 37.5 pounds

4) Resultant Force, Fr

x-component: Fr,x

Fr,x = F1,x + F2,x = 121.24 pounds - 64.95 pounds = 56.29 pounds

y-component: Fr,y

Fr,y = F1,y + F2,y = 70 pounds + 37.5 pounds = 107.5 pounds

4.1) magnitude

|Fr| = √ [ (56.29 pouns)^2 + (107.5 pounds)^2 ] = 121.35 pounds.

4.2) direction

tan(α) = Fr,y / Fr,3 = 56.29 pounds / 107.5 pouns = 0.5236

=> α = arctan(0.5236) = 27.64 °


5 0
3 years ago
I’m stuck please help
andrew-mc [135]
You divide 3 on both sides then you equation is the square root of -4x-4 =4 and you square the number on both sides because u need to do the same things on both sides and you get -4x-4=16 subtract by 4 on boyh sides to get -4x=20 and divide by -4 on both aises to get x=-5

I hope this helped i know this explanation is a bit wonky

7 0
3 years ago
Teri hits 14 out of 20 tries What is the experimental probability that she will hit the target on her next try.
Sauron [17]

Answer:

70%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
R-32=2 please Help me on this
erik [133]

Answer:

r = 34

Step-by-step explanation:

add 32 to both sides,

5 0
3 years ago
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