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faltersainse [42]
3 years ago
7

If $1,000 is invested at 16% interest, compounded annually,

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

Answer:

equation; P=A(1+r/n)^nt

P=principal amount

A=value of investment

r= interest rate in decimals

n=number of times compounded

t=time in years

P=1000(1+0.16/12)^12(5)= $2213.8 rounded

Step-by-step explanation:

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What is the solution to 8x - 3(2x - 4) = 3(x - 6)?<br> A.30<br> B.2<br> C.6<br> D.No solution
anyanavicka [17]

Answer: A.30

Step-by-step explanation:

Let's solve your equation step-by-step.

8x−3(2x−4)=3(x−6)

Step 1: Simplify both sides of the equation.

8x−3(2x−4)=3(x−6)

8x+(−3)(2x)+(−3)(−4)=(3)(x)+(3)(−6)(Distribute)

8x+−6x+12=3x+−18

(8x+−6x)+(12)=3x−18(Combine Like Terms)

2x+12=3x−18

2x+12=3x−18

Step 2: Subtract 3x from both sides.

2x+12−3x=3x−18−3x

−x+12=−18

Step 3: Subtract 12 from both sides.

−x+12−12=−18−12

−x=−30

Step 4: Divide both sides by -1.

−x/-1 = -30/-1

<h3>x=30</h3>
7 0
3 years ago
___:21=5:7 helppp me pleasee
rusak2 [61]

Answer:

15:21 = 5:7

Step-by-step explanation:

21/7 = 3

5 x 3 = 15

3 0
2 years ago
Why does it takes 3 copies of 1/6 to show the same amount as 1copy of 1 / 2
Veseljchak [2.6K]
Because 1/2 ≠ 1/6.

We know that 1/6 < 1/2, so we can set up an equation to see how many copies are needed for them to be equal.

(1/6)x = 1/2
[(1/6)x] × 6 = [1/2] × 6
x = 6/2 = 3

This equation shows that 1/6 × 3 = 1/2, therefore we need 3 copies of 1/6 to equal 1 copy of 1/2.
3 0
3 years ago
Read 2 more answers
Find the following integral. <br> Integrate x + 5/x^2 +10x +26 dx
sweet-ann [11.9K]

Given :

Polynomial , f(x)=x+\dfrac{5}{x^2}+10x+26 .

To Find :

Integration of f(x) .

Solution :

We know , integration of x^n is :

\int x^n \, dx = \dfrac{x^{n+1}}{n+1}+C

( Here , is C is a constant )

Now ,

\int f(x)\ dx=\int( x+\dfrac{5}{x^2}+10x+26)dx\\                  \\                 \int f(x)\ dx= \int x\ dx+\int 5x^{-2}\ dx+\int 10 x \ dx +26\ dx\\                 \\                 \int f(x)\ dx=\dfrac{x^2}{2}+\dfrac{5\times x^{-1}}{(-1)}+\dfrac{10x^2}{2}+26x+C\\\\                 \int f(x)\ dx=\dfrac{11x^2}{2}+26x-5x^{-1}+C

Therefore , the integration is \dfrac{11x^2}{2}+26x-5x^{-1}+C .

Hence , this is the required solution .

6 0
3 years ago
A restaurant uses 33 pounds of pasta for a party of 14 people. If they are cooking pasta for a party of 5656 people, what should
Hoochie [10]
5656people(33lbs/14people)=13332 lbs  
4 0
3 years ago
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