Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So

Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
Answer:
2111.15
Step-by-step explanation:
A=2π*r*h+2π*r^2
You plug in your height and radius into the formula for surface area of cylinder
The answer is 5x-59
To get this answer you have to follow pemdas and remember you can’t add variables to non variables, so you just expand the equation
As an example
5x + 6 -2x +7
You would get
13-3x