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RoseWind [281]
3 years ago
10

Simplify 5 square root 45

Mathematics
1 answer:
tangare [24]3 years ago
6 0
I hope this helps you

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Oxford currently generates 45,000 tons of garbage per year. but the city is launching some recycling initiatives to bring that n
barxatty [35]

Answer:

-Exponential Decay

-Decay factor is (1-0.05)

Step-by-step explanation:

-Given that the number decreases by a defined rate each year from the initial size by 5%,

-This is an exponential decay function of the form:

y=Ae^{-rt}

Where:

y is the quantity/size after time t

A is the initial size

r is the rate of decay

-Our function can the be written as

y=45000e^{-0.05t}

Hence, the decay rate/factor is 0.05

#Alternatively

The exponential decay can be of the form:

y=ab^x

Where:

y is the size at time x, a is the initial size, x is time and b is the decay factor.

b is of the form b=(1-r),\ \  r=decay\  rate

y=ab^x\\\\y=45000(1-0.05)^x

Hence, the decay factor is (1-0.05)

8 0
3 years ago
In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

5 0
3 years ago
If the temperature is 7 degrees below zero and then rises 3 degrees,will the final temperature be positive or negative
sladkih [1.3K]
It would be negative cz it would add up to -4
6 0
3 years ago
Read 2 more answers
Find the derivative of StartFraction d Over dx EndFraction Integral from 0 to x cubed e Superscript negative t Baseline font siz
Valentin [98]

Answer: (a) e ^ -3x (b)e^-3x

Step-by-step explanation:

I suggest the equation is:

d/dx[integral (e^-3t) dt

First we integrate e^-3tdt

Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.

(b) to differentiate the integral let x = t, and substitute into the expression.

Therefore dx = dt

Hence, d/dx[integral (e ^-3x dx)] = e^-3x

8 0
4 years ago
Read 2 more answers
When you are trying to find the endpoint when given the midpoint and one point, what would the new formula be? Manipulate the fo
MariettaO [177]

Answer:

(x_2,y_2) = (2x_m - x_1 ,2y_m - y_1 )

Step-by-step explanation:

Given

\left(\frac{x_1+\:x_2}{2},\:\:\frac{y_{1\:}+y_2}{2}\right)\:=\:\left(x_m,\:y_m\right)

Required

Determine x2, y2

Start by splitting the expression

x_m = \left(\frac{x_1+\:x_2}{2}) and y_m = (\frac{y_{1\:}+y_2}{2})

Solving for x2 in x_m = \left(\frac{x_1+\:x_2}{2})

Multiply through by 2

2 * x_m = \frac{x_1 + x_2}{2} * 2

2x_m = x_1 + x_2

Make x2 the subject;

x_2 = 2x_m - x_1

Similarly:

y_m = (\frac{y_{1\:}+y_2}{2})

Multiply through by 2

2 * y_m = \frac{y_1 + y_2}{2} * 2

2y_m = y_1 + y_2

Make y2 the subject;

y_2 = 2y_m - y_1

Hence:

(x_2,y_2) = (2x_m - x_1 ,2y_m - y_1 )

7 0
3 years ago
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