Question

if ABC is a isosceles triangle with sides(2a+b)cm, (6a+2b+1)cm and a base of 4a cm, if it's perimeter is 28 find sides​

Answer 1

Answer:

a=1.5, b= 3

Step-by-step explanation:

sum of all sides will give us perimeter. Therefore

2a+b+6a+2b+1+4a=28

12a+3b+1=28

12a+3b=27....eqn1

since t two sides of this isosceles triangle are equal:

2a+b=4a

2a=b

$a=\frac{b}{2}$

substituting $\frac{b}{2}$$.$ in the first equation whenever we encounter a we will have:

$12(\frac{b}{2})+3b=27$

6b+3b=27

9b=27

b=3

therefore $a= \frac{b}{2} =\frac{3}{2} =1\frac{1}{2} or 1.5$