I think the best option here is B. <span>period 2pi/3 and asymptote at x=0
</span>because period of tanx is pi so period of tan(3/2x) is pi/(3/2) = 2pi/3. I hope this can work good for you.

3 0

3 years ago

If a stone is thrown down at 170 feet per second from a height of 1,020 feet, its height after t seconds is given by

andreyandreev [35.5K]

Step-by-step explanation:

It is given that,

Initial speed of the stone, u = 170 ft/s

It is thrown down from a height of 1020 feet.

We need to its height after t seconds. It can be calculated using second equation of kinematics as follows :

$h=ut-\dfrac{1}{2}gt^2+h_0$

h₀ is initial height, u = -170 ft/s as the stone is throwing down and g = -32ft/s²

Putting values, we get :

$h=-170t-\dfrac{1}{2}\times 32t^2+1020\\\\h=-16t^2-170t+1020$

4 0

3 years ago