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tia_tia [17]
3 years ago
9

What function equation is represented by the graph?

Mathematics
2 answers:
jek_recluse [69]3 years ago
4 0
The slope (m) of the line graphed is -4/2, because the line goes down 4 (-4) and over 2 (+2), which is change in y over change in x
m = -4/2 = -2
the y-intercept (b) of the line = -1, because the line crosses the vertical line at x=0 at y=-1
now for the equation:
y = mx + b
y = -2x + -1 = -2x - 1
f(x) = -2x-1
the last answer is correct
Natali5045456 [20]3 years ago
4 0

Answer:

f(x)=−2x−1

Step-by-step explanation:


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If ABCD is a square and AB = 10, what is the measure of BD? (rounded to the nearest hundredth) A) 7.07 B) 14.14 C) 19.21 D) 28.2
damaskus [11]

Answer:

B)14.14

Step-by-step explanation:

a square is made of 2 right triangles

the two legs of one right triangle are both 10 so

using Pythagorean theorem we get the square root of 10^2+10^2

this solves to the square root of (200)

which is ≈ 14.14...

6 0
2 years ago
A highway traffic condition during a blizzard is hazardous. Suppose one traffic accident is expected to occur in each 60 miles o
o-na [289]

Answer:

a) 0.3408 = 34.08% probability that at least one accident will occur on a blizzard day on a 25 mile long stretch of highway.

b) 0.0879 = 8.79% probability that two out of these six blizzard days have no accident on a 25 mile long stretch of highway.

c) 0.4493 = 44.93% probability of no damaging accidents requiring a insurance claims on an 80 mile stretch of highway.

Step-by-step explanation:

We have the mean for a distance, which means that the Poisson distribution is used to solve this question. For item b, the binomial distribution is used, as for each blizzard day, the probability of an accident will be the same.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose one traffic accident is expected to occur in each 60 miles of highway blizzard day.

This means that \mu = \frac{n}{60}, in which 60 is the number of miles.

(a) What is the probability that at least one accident will occur on a blizzard day on a 25 mile long stretch of highway?

n = 25, and thus, \mu = \frac{25}{60} = 0.4167

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.4167}*(0.4167)^{0}}{(0)!} = 0.6592

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.6592 = 0.3408

0.3408 = 34.08% probability that at least one accident will occur on a blizzard day on a 25 mile long stretch of highway.

(b) Suppose there are six blizzard days this winter. What is the probability that two out of these six blizzard days have no accident on a 25 mile long stretch of highway?

Binomial distribution.

6 blizzard days means that n = 6

Each of these days, 0.6592 probability of no accident on this stretch, which means that p = 0.6592.

This probability is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.6592)^{2}.(0.3408)^{4} = 0.0879

0.0879 = 8.79% probability that two out of these six blizzard days have no accident on a 25 mile long stretch of highway.

(c) If the probability of damage requiring an insurance claim per accident is 60%, what is the probability of no damaging accidents requiring a insurance claims on an 80 mile stretch of highway?

Probability of damage requiring insurance claim per accident is of 60%, which means that the mean is now:

\mu = 0.6\frac{n}{60} = 0.01n

80 miles:

This means that n = 80. So

\mu = 0.01(80) = 0.8

The probability of no damaging accidents is P(X = 0). So

P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493

0.4493 = 44.93% probability of no damaging accidents requiring a insurance claims on an 80 mile stretch of highway.

6 0
2 years ago
What is the value of largest integers x such that 112/2^x is an integer.​
Gennadij [26K]

Answer:

x = 4

Step-by-step explanation:

16 × 7 = 112

2^4 = 16

so that is the answer

6 0
2 years ago
Mal always solve the equation of negative 5 x minus 16 equals 8, his work is shown below identify the era where it was made step
Digiron [165]

Given:

The equation is

-5x-16=8

To find:

The error and correct solution.

Solution:

We have,

-5x-16=8

Add 16 on both sides.

-5x-16+16=8+16

-5x=24

Divide both sides by -5.

\dfrac{-5x}{-5}=\dfrac{24}{-5}

x=-\dfrac{24}{5}

Third step is incorrect because he divide the equation by 5 instead of -5.

Therefore, the correct solution is x=-\dfrac{24}{5}.

3 0
3 years ago
Which function could be represented by the graph on the coordinate plane?
posledela

Answer:

It D

Step-by-step explanation:

5 0
2 years ago
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