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nekit [7.7K]
3 years ago
15

Solve the following problems 4 6\5+2 3\4

Mathematics
2 answers:
notka56 [123]3 years ago
4 0
You can use Cymath. Just enter the equation
https://www.cymath.com
german3 years ago
3 0

Answer:

7 19/20 = 7.95

Step-by-step explanation:

I assume you mean 4+6/5 + 2+3/4

Commutative property

4+2+6/5+3/4

Associative property

(4+2)+(6/5+3/4) = 6 + (6/5+3/4)

Multiply by 1

6/5*4/4 +3/4*5/5

24/20+15/20

39/20+6 = 6+1+19/20 = 7+19/20

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There are 5 sales person and 22 clients if of each client only deals with one sales person and the client are divided as equally
Mariana [72]

Answer:

2 sales person

Step-by-step explanation:

If there are 5 sales person and 22 clients

Therefore:

1 sales Person will be responsible for \frac{22}{5}=4\frac{2}{5} Client.

Therefore: 2 sales person will be responsible for 5 clients since there must be equal distribution.

4 0
4 years ago
Which value of x makes the equation x +8=15 true?
tiny-mole [99]

Answer:

<h2>7</h2>

Step-by-step explanation:

<h3>x+8=15</h3><h3>x=15-8</h3><h3>x=7</h3>

<h2>HOPE IT HELPS</h2>
3 0
3 years ago
1)An exam worth 172 points contains 30 questions. Some questions are worth 2 points, and the others are worth 9 points. How many
lisabon 2012 [21]
1) x+y=302x+9y=172x=-y+30-2y+60+9y=1727y=112y=16x=14
14 2-point questions and 16 9-point questions
2) c+a=163
6c+13a=1566
c=-a+163
-6a+976+13a=1566
7a=588
a=84
c=79
84 adult tickets and 79 children tickets
3) a+c=15; ax+cy=132
8+7=15; 8x+7y=132

a+c=9; ax+cy=72
4+5=9; 4x+5y=72

8x+7y=132
4x+5y=72
(8x+10y)=(144)

8x=-7y+132
8x=-10y+144
-7y+132=-10y+144
3y=12
y=4
4x+20=72
4x=52
x=13
The price for an adult ticket is $13 and the price for a child ticket is $4
3 0
3 years ago
Write an algebraic Expression for three more cookies than are in the jar
miss Akunina [59]

Answer:

x+3

Step-by-step explanation:

You don't know how many cookies there are in a jar, therefore it is (x). You would add 3 to the jar.

8 0
3 years ago
If K is the midpoint of segment JL, JK = 2x+10 and KL = 3x-12 find J
Gennadij [26K]

I hope this helps you

4 0
3 years ago
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