Draw a basketball with a vertical, angled, and horizontal cut
1 answer:
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Answer:
6 (assuming the units is in centimetres)
Step-by-step explanation:
Hi, hope this helps!
Method 1:
Calculate this shape as a trapezium. This is a trapezium because it has one pair of parallel sides. The way to calculate the area of a trapezium is this:
- Half the sum of the parallel sides
- Multiply the perpendicular height between them
In this case, 4 and 2 are parallel, so we add them together (4 + 2 = 6) then we divide by two (6 ÷ 2 = 3). Then we multiply our answer by the perpendicular length between the two parallel sides (assuming the side on the left is at a right-angle, 3 x 2 = 6).
Method 2:
Calculate this shape as a rectangle + a triangle. If you split the shape so the pointy bit on the right becomes a triangle and the left becomes a square, you can calculate the area without knowing the formula for calculating a trapezium (see above ^).
- Area of the square / rectangle = length x width = 2 x 2 = 4
- Area of the triangle = 1/2 x length x width = 2 x 2 x 1/2 = 4 x 1/2 = 4 ÷ 2 = 2
Then we add the two areas together (4 + 2 = 6).
I hope this helped and I wasn't waffling on :)
Bluey
Hope this was what you’re looking for ^.^
(If correct, if you don’t mind can you please mark me as the brainliest, it’s okay if not)
(If correct, if you don’t mind can you please mark me as the brainliest, it’s okay if not)