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notsponge [240]
3 years ago
14

Solve log2 [log3 (log4 x)]=0​

Mathematics
1 answer:
vfiekz [6]3 years ago
6 0
The correct answer is 2
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6cos(20πt-π)+6√3cos(20πt-π\2)
juin [17]

Answer:

<u>Answer</u><u> </u><u>is</u><u> </u><u>-</u><u>6</u><u>t</u>

Step-by-step explanation:

{ \tt{ = (6 \cos(20\pi t)  \cos(\pi)  +  6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t)  \cos( \frac{\pi}{2} )  +  \sin(20\pi t)   \sin( \frac{\pi}{2} )) }} \\  = { \tt{ (- 6t + 0) + (0 + 0)}} \\  = { \tt{ - 6t}}

Note that π is 180°

5 0
2 years ago
Draw a triangle that is both a right triangle and an isosceles triangle. You can use either pencil and paper, or a draw program.
dem82 [27]
2. measurements can be any to complementary angles.
   for example, 60 & 30
3. the 2 sides are equal. Since it is an isosceles triangle.
4.an equi.triangle can never be right angled. Since, all angles are 60° in an             equi.triangle.
5. right triangle can never have an obtuse angle since one angle is already          90°. therefore the other two agles are supposed to be acute angles.[ since        sum of all angles in a triangle is 180°]
6 0
3 years ago
10 is 5% of what number
GarryVolchara [31]
We can use proportion to get the result
10 ----------- 5%
x ------------- 100%
Crossmultiply proportion

5*x=10*100
5x=1000     /:5 divide both sides by 5
x=1000:5
x=200 - its the answer


6 0
3 years ago
Read 2 more answers
Can you please help me ​
mylen [45]

Answer:

3

Step-by-step explanation:

please remember when dividing letters or numbers of the same base then their exponents will be minused.

4 0
3 years ago
Please calculate the probability using the following equations (in document)
labwork [276]

Substitute <em>u</em> = <em>t</em> ³/2592 and d<em>u</em> = <em>t</em> ²/864 d<em>t</em>. Then

P(T)=1-\displaystyle\int_0^T f(t)\,\mathrm dt=1-\displaystyle864\left(1.1574\times10^{-3}\right)\int_0^{\frac{T^3}{2592}}e^{-u}\,\mathrm du

The probability that a 12 hour surgery is successful is <em>P</em> (12), so letting <em>T</em> = 12 gives

P(12)\approx1-\displaystyle\int_0^{\frac23}e^{-u}\,\mathrm du\approx e^{-\frac23} \approx \boxed{0.5134}

4 0
3 years ago
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