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love history [14]
2 years ago
14

Simplify 2(a + 3b) + 3(4a + b). (A) 6a+6b (B) 14a + 9b (C) 14a + 4b (D) 6a+ 7b

Mathematics
1 answer:
Oduvanchick [21]2 years ago
4 0

Answer: = 14a + 9b

Step-by-step explanation:

<em>distribute:</em>

2(a+3b) + 3(4a+b)

2a + 6b + 12a + 3b

<em>combine like terms: </em>

2a + 6b + 12a + 3b

14a + 6b + 3b

14a + 6b + 3b

<u>= 14a + 9b</u>

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Three consecutive integers add to 567. Find the integers. PLEASE HELP
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Consecutive integers mean one after the other and their difference would one more or less.

Let the numbers be x, x +1, x +2.

Therefore x + (x+1) + (x +2) = 567
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               3x = 567 -3 = 564
               3x = 564  Divide by 3.
                 x  = 564/3
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Therefore integers  x, x +1, x +2 = 188, 188+1, 188+2.
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Cheers.
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Answer:

Step-by-step explanation:

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