By using distance formula (which is attached below), you can solve this problem:
√(x2-x1)^2+(y2-y1)^2
(5, -1) and (5, 3)
√(5-5)^2+(3-(-1))^2
√0^2+4^2
√0+16
√16
4
The distance between the two points is 4.
The sum of the two bases is twice the length of the mid segment
24+x=19*2
x=14
D, because there are several students that are in your school. There would be many different answers.
If you know that y = 6. You just have to switch Y by 6.
x + 2y = 16
x + 2*6 = 16
x + 12 = 16
x = 16 - 12
x= 4
4 + 2*6 = 16
Hope this helps !
Photon
The answer would be 54, because A= PQ over 2 = 9 x 12 over 2 = 54
