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loris [4]
3 years ago
10

Does x=3/y show direct variation ​

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

No it does not. when solved you should get y=3/x, meaning it shows inverse variation.

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suppose you spina spinner numbered 1 through 6, and you sa 3 five times in a row.What is the theoretical possibility of spinning
sertanlavr [38]
It would still be a 1/6th chance that you will gey the number three. i would say that just because you got 3 5 times in a row will not increase or decrease your chances of another 3.
5 0
3 years ago
Can you solve this in a complete answer
I am Lyosha [343]
A 90 degree clockwise rotation about origin followed by a transition 2 units to the right
8 0
2 years ago
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









4 0
2 years ago
54 as a product of primes
kvasek [131]
54 can be factored as follows:

54

2*27

2*3*9

2*3^2*3

2*3^3

Therefore, 54 is equal to 2*3^3, or 2*3*3*3.
6 0
2 years ago
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