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3 years ago

Charlize and camille solved the equation 4x-2y=8 for y

Mathematics

2 answers:

geniusboy [140]3 years ago

7 0

Answer:

bye

Step-by-step explanation:

Yakvenalex [24]3 years ago

5 0

Answer:

Very interesting

Step-by-step explanation:

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Solve. <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%20x%20-%2011%7D%20%20-%20%20%5Csqrt%7Bx%7D%20%20%2B%205%20%3D%206" id

ICE Princess25 [194]

Solve for x:
5 - sqrt(x) + sqrt(3 x - 11) = 6

Subtract 5 from both sides:
sqrt(3 x - 11) - sqrt(x) = 1

(sqrt(3 x - 11) - sqrt(x))^2 = -11 + 4 x - 2 sqrt(x) sqrt(3 x - 11) = -11 + 4 x - 2 sqrt(x (3 x - 11)) = 1:
-11 + 4 x - 2 sqrt(x (3 x - 11)) = 1

Subtract 4 x - 11 from both sides:
-2 sqrt(x (3 x - 11)) = 12 - 4 x

Raise both sides to the power of two:
4 x (3 x - 11) = (12 - 4 x)^2

Expand out terms of the left hand side:
12 x^2 - 44 x = (12 - 4 x)^2

Expand out terms of the right hand side:
12 x^2 - 44 x = 16 x^2 - 96 x + 144

Subtract 16 x^2 - 96 x + 144 from both sides:
-4 x^2 + 52 x - 144 = 0

The left hand side factors into a product with three terms:
-4 (x - 9) (x - 4) = 0

Divide both sides by -4:
(x - 9) (x - 4) = 0

Split into two equations:
x - 9 = 0 or x - 4 = 0

Add 9 to both sides:
x = 9 or x - 4 = 0

Add 4 to both sides:
x = 9 or x = 4

5 - sqrt(x) + sqrt(3 x - 11) ⇒ 5 - sqrt(4) + sqrt(3×4 - 11) = 4:
So this solution is incorrect

5 - sqrt(x) + sqrt(3 x - 11) ⇒ 5 - sqrt(9) + sqrt(3×9 - 11) = 6:
So this solution is correct

The solution is:
Answer: x = 9

5 0

3 years ago

A rectangle has a length 6 meters longer than double the width. The perimeters is i44 meters. Find the dimensions of the rectang

Oksana_A [137]

Use the information to form an equation
x = width
x + 6 = length
perimeter = length + length + width + width
x + x + x + 6 + x + 6 = 44
4x + 12 = 44
4x = 32
x = 32/4
x = 8
width = 8 meters
length = 8 + 6 = 14 meters

8 0

3 years ago

the vertices of triangle PQR are P(-3, 8), Q(-6, -4), and R(1, 1). If you reflect triangle PQR across the x-axis, what will be t

otez555 [7]

Answer:

The coordinates of the vertices of the image will be:

P'=(-3,-8)

Q'=(-6,4)

R'=(1,-1)

Step-by-step explanation:

If you reflect a point P=(x,y) across the x-axis, the coordinates of the image will be P'=(x,-y), then:

P=(-3,8)=(xp,yp)→xp=-3, yp=8→P'=(xp,-yp)→P'=(-3,-8)

Q=(-6,-4)=(xq,yq)→xq=-6, yq=-4→Q'=(xq,-yq)=(-6,-(-4))→Q'=(-6,4)

R=(1,1)=(xr,yr)→xr=1, yr=1→R'=(xr,-yr)→R'=(1,-1)

3 0

3 years ago

Twelve diminished by six times a number

Vilka [71]

Twelve diminished by six times a number

12 - 6x

3 0

3 years ago

Ms.Lopez has created a floor plan of a dollhouse. The area of the entire dollhouse is 576 square inches

harina [27]

Answer:

(a)Area of the bedroom=96 square inches

(b)Area of the living room =144 square inches

(c)Area of the dollhouse that is not of the bedroom or living room =336 square inches.

Step-by-step explanation:

The area of the bedroom is 1/6 the area of the entire dollhouse

The area of the living room is 3/2 times the area of the bedroom.

The area of the entire dollhouse is 576 square inches

Let the area of bedroom=b

Let the area of living room=l

(a) The area of the bedroom is 1/6 the area of the entire dollhouse

$b=\frac{1}{6}X576=96$ square inches

(b)The area, in square inches, of the living room

The area of the living room is 3/2 times the area of the bedroom

l= $\frac{3}{2}X96=144$ square inches

(c)The total area of the house =576 square inches

Area of the bedroom=96 square inches

Area of the living room =144 square inches

Area of the dollhouse that is not of the bedroom or living room

=576-(96+144)=576-240=336 square inches.

The area of the living room is 3/2 times the area of the bedroom

This is gotten by subtracting the area of the bedroom and living room from the total area of the house.

3 0

3 years ago