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zhannawk [14.2K]

2 years ago

9

Let E be the event where the sum of two rolled dice is greater than or equal to 7. List the outcomes in Ec.

1 answer:

zhenek [66]2 years ago

4 0

Answer:

(1, 1) (1, 2) (1, 3) (1,4)

(1,5) (2,1) (2,2) (2,3)

(2,4) (3,1) (3,2) (3,3)

(4,1) (4,2) (5,1)

Step-by-step explanation:

You might be interested in

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

irina [24]

1st number = n
2nd number = n+1
3rd number = n+2

sum of the squares of 3 consecutive numbers is 116

n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.

5 0

2 years ago

The expression below is a factorization of what trimonial (5x+6)(3x-2)

STatiana [176]

Answer:

$15x^2 + 8x -12$

Step-by-step explanation:

(5x+6)(3x-2)

"foil" it out

F: 5x * 3x = 15x^2

O: 5x * -2 = -10x

I: 6*3x = 18x

L: 6 * -2 = -12

3 0

2 years ago

Read 2 more answers

Help me ASAP plz!!!!

elena55 [62]

(2, -1), (6,- 4), and (6, -1). Hope this helps man!

6 0

2 years ago

Read 2 more answers

Given f(x) = 5x - 3, find f(-2).

lukranit [14]

Answer:

-13

Step-by-step explanation:

Subsitude -2 to where x is and you get -1o then subtract by -3 and the total is -13

3 0

3 years ago

Read 2 more answers

Which of the points listed below is not on the line with equation 7y+2=3x-5

kicyunya [14]

Answer: Second option.

Step-by-step explanation:

Given the folllowing Linear Equation:

$7y+2=3x-5$

You need to substitute the coordinates of each point given in the options into the equation and then evaluate.

1) Substituting $(2, -\frac{1}{7})$ into the equation, you get:

$7(-\frac{1}{7})+2=3(2)-5\\\\-1+2=6-5\\\\1=1\ (TRUE)$

2) Substituting the point $(3, -\frac{3}{7})$ . you get:

$7(-\frac{3}{7})+2=3(3)-5\\\\-3+2=9-5\\\\-1=4\ (FALSE)$

3) Apply the same procedure using the point $(1, -\frac{4}{7})$ :

$7(-\frac{4}{7})+2=3(1)-5\\\\-4+2=3-5\\\\-2=-2\ (TRUE)$

4) Apply the same procedure using the point $(-1, -\frac{10}{7})$

$7(-\frac{10}{7})+2=3(-1)-5\\\\-10+2=-3-5\\\\-8=-8\ (TRUE)$

5) Substituting $(0,-1)$ into the equation:

$7(-1)+2=3(0)-5\\\\-7+2=-0-5\\\\-5=-5\ (TRUE)$

Therefore, the point $(3, -\frac{3}{7})$ is not on the given line.

8 0

3 years ago