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Nikitich [7]
3 years ago
7

10 points

Mathematics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

w = 33.94 ft

Step-by-step explanation:the roof takes the shape of a right angle. The top of the roof is a right angle. To find the width of the house, which is the hypotenuse of the triangular roof, we would apply pythagorean theorem.

Thus:

w^2 = 24^2 + 24^2

w^2 = 1,152

Square both sides

\sqrt{w^2} = \sqrt{1,152}

w = 33.94 (to 2 decimal places)

The width of the house = 33.94 ft

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I’ll give brainliest pls help
andrew11 [14]

Answer:

The slopes of WX and XZ

Step-by-step explanation:

The singular factor that determines if the parallelogram is a rectangle are the angles at the edges

Mathematically, we can only have a rectangle if there are four right angles with one right angle each at the edges of the rectangle

So, by having the slope of the sides forming the width and that which forms the length, we can deduce if what we have is rectangle given that the slopes will yield a perpendicular product

Hence, the slopes of WX and XZ can be calculated to show this

7 0
3 years ago
Find the​ mean, median, and mode of the​ data, if possible. If any of these measures cannot be found or a measure does not repre
Contact [7]

Answer:

1. Median = 10.1

2. A. The median represents the center.

3. D. The​ mode(s) can't represent the center because it​ (they) is​(are) not a data value.

Step-by-step explanation:

Mean of a sample = sum of the samples/no of the samples

Samples in increasing order:

9.8

9.8

9.9

10.1

10.4

10.6

11.1

Mode is the sample with highest frequency.

Median is the middle entry of the data.

Mean = (9.8 + 9.8 + 9.9 + 10.1 + 10.4 + 10.6 + 11.1)/7

= 717/7

= 10.243

Median = 10.1

Mode = 9.8 because it has the highest frequency of 2

6 0
4 years ago
Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%
garri49 [273]

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

<h3>LHS</h3>

\boxed{\sf \dfrac{cosA}{sinA}=cotA}

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

\\ \sf\longmapsto 1-cot2A

\\ \sf\longmapsto 1-\dfrac{1}{tan2A}

\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}

\\ \sf\longmapsto tan2A

8 0
3 years ago
A group of which of the order must be cyclic?<br><br> A. 6 <br> B. 7 <br> C. 8 <br> D. 9
DochEvi [55]

Answer:

Its option D. 9

mark me as brainlist

3 0
3 years ago
The height after t seconds of an object projected upward with an initial velocity of 48 feet per second from a 210-foot tower ca
svetlana [45]

Given:

The height h of an object after t seconds is

h=-16t^2+48t+210

The height of a neighboring 50-foot tall building is modeled by the equation h=50.

The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.

To find:

The statement which describes the validity of these solutions.

Solution:

We have,

h=-16t^2+48t+210

Here, t is the time in seconds.

For t=-2,

h=-16(2)^2+48(-2)+210

h=-64-96+210

h=50

For t=5,

h=-16(5)^2+48(5)+210

h=-400+240+210

h=50

So, the value of h is 50 at t=-2 and t=5.

We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.

The solution t = 5 is the only valid solution to this system since time cannot be negative.

Therefore, the correct option is C.

6 0
3 years ago
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