2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
A number can replaced with a variable like x
(X+3)4=16
4x+12=16
4x=4
X=1
(X/4)+3=24
X/4=21
X=84
The answer is 27a^6
Hope this helps.
Answer:
Lose the ability to cry because i dont cry that much
Step-by-step explanation: