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3 years ago

How do you identify if the equation is linear, exponential, or quadratic?

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

Answer:

It's form. Linear is a normal line, exponential is a curvy line, and quadratic is a u shape with the vertice on the y-axis line, making half of the u on the left quadrant and the other half on the right quadrant

Step-by-step explanation:

first is linear, second is exponential and third is quadratic

vodka [1.7K]3 years ago

3 0

Answer:

quadratic needs to have a degree of 2, linear equations are in form y=mx+b and do not have exponents

Step-by-step explanation:

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(x+6) + (x+8) + 14 / 2

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I really need help. Find a. Round to the nearest tenth.

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a ≈ 1.8

Step-by-step explanation:

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2 years ago

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3 years ago

What equation is graphed in this figure?

topjm [15]

Answer:

The third equation: $y+2=-3(x-1)$

Step-by-step explanation:

The two points on the line are $(-1,4)$ and $(1,-2)$ .

Slope of the line passing through two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$m=(y_{2} -y_{1})/ (x_{2} -x_{1})$

Here, $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are $(-1,4)$ and $(1,-2)$ .

Therefore, slope is equal to, $m=(-2-4 )/ (1-(-1)$

$m=-6/2$

$m=-3$

Now, equation of a straight line with slope m and points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$y-y_{1}=m(x-x_{1})\\y-y_{2}=m(x-x_{2})$

Now, if we use the 2nd form, then $x_{2}=1,y_{2}=-2$ .

So, the equation is given as :

$y-(-2)=-3(x-1)\\y+2=-3(x-1)$

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3 years ago