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AleksandrR [38]
2 years ago
15

Answer pleaseeeeeeeeeeeeeee

Mathematics
1 answer:
Inessa [10]2 years ago
8 0

Answer:

A. Square

Step-by-step explanation:

Hope this helps!

Please mark brainliest! Thanks!

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When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither nu
o-na [289]
The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:

x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
3 0
3 years ago
Which expression represents the product of x^3 +2x - 1 and x^4 -x^3 +3?
Butoxors [25]

Answer:

second to the longest one is right

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the value of x.
prohojiy [21]
X would be 90° ... every x is 90°
3 0
3 years ago
Algebra homework jimthompson
Gnesinka [82]

Answers:

  1. B) 66%
  2. C) 34%
  3. See the diagram below
  4. C) 86% of the people who studied passed the quiz.

===================================================

Explanations:

Problem 1

We have B = 62+32 = 94 people who wear a belt. Of this total, A = 62 belt wearers also have a watch. So A/B = 62/94 = 0.6596 = 65.96% = 66% of the belt wearers have a watch. This value is approximate.

-------------------------------

Problem 2

In the previous problem we found that roughly 66% of the belt wearers have a watch. This must mean about 100% - 66% = 34% of the belt wearers do not have a watch.

-------------------------------

Problem 3

The question is "<u>Among left handers, what proportion has neat handwriting?</u>" which means we're effectively only concerned with the first row that says "left-handed". In this row, there are 5 who write neat, and 10 who do not. We have B = 5+10 = 15 people who are left-handed. We'll divide everything in this row by this value of B.

So for A = 5, it turns into the approximate proportion A/B = 5/15 = 0.33 meaning that about 33% of the left-handers have neat handwriting.

For the other value in this row, A = 10 turns into A/B = 10/15 = 0.67 = meaning that about 67% of the left-handers have messy hand writing.

You'll do the same thing for row 2, but you'll divide everything by B = 65 (because there are 34+31 = 65 right-handed people total).

The filled out table is shown below.

-------------------------------

Problem 4

Let's say we ignore the percentage signs. Adding the values across the first row gets us B = 86+14 = 100 people who passed the quiz. Of that, A = 86 people who passed also studied as shown in the top left corner.

We can then see that A/B = 86/100 = 86% of the people who passed the quiz also studied. Notice the phrasing here. It's <u>not</u> the other way around. We would not say "86% of the people who studied passed the quiz". Your teacher has the order swapped unfortunately. If choice C said "86% of the people who passed the quiz studied for the test", then it would be fully correct. However, I think that's what they were going for and made a typo.

If we did state that "86% of the people who studied passed the quiz", then we'd be considering the first column instead of the first row. However, note how the percentages in the first column do not add to 100%.

7 0
3 years ago
Please answer the 3rd Question please answer it fast............I WILL MARK YOU AS THE BRANLIEST.................
mojhsa [17]

since LM=LN there values are same which is given as 5.5 cm and MN =7cm

now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs  will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!

Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.

<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>

8 0
3 years ago
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