Find three consecutive intergers such that the sum of twice the smallest and 3 times the largest is 126
1 answer:
Answer:Answer:
24
,
25
,
26
Step-by-step explanation:
Let's call the smallest integer
n
. Then the next two consecutive integers are
n
+
1
and
n
+
2
.
"Sum of twice the smallest and 3 times the largest is 126"
2
(
n
)
+
3
(
n
+
2
)
=
126
2
n
+
3
n
+
6
=
126
5
n
+
6
=
126
5
n
=
120
n
=
24
So the smallest integer is
24
.
The three consecutive integers are then:
24
,
25
, and
26
.
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