Answer:
(36π -72) cm²
Step-by-step explanation:
The area of a segment that subtends arc α (in radians) is given by ...
A = (1/2)r²·(α - sin(α))
Here, you have r = 12 cm and α = π/2 radians, so the area of the segment is ...
A = (1/2)(12 cm)²·(π/2 -1) = (36π -72) cm²
Answer:
Follows are the solution to the given question:
Step-by-step explanation:
There are missing details, which is why its solution is as follows:
When an angle bisector points so, its two sides of the corner are equidistant. Its corner bisector of a triangle angle is a straight line splitting its angle into two congruent directions. In such a single point, calling its incentives, follow three-angle engineers are required of its three triangle angles.
X is 6 because it’s a 45 45 90 triangle. X and Y are the same length and Y is whatever y is *square root of 2.
Answer:
Mia has a bag that contains a letter block for each of the 26 letters of the alphabet. She draws a letter block from the bag, writes down the letter, and puts the block back in the bag. She repeats this 26 times. The results show that she drew a vowel (A, E, I, O, or U) 6 times.
Step-by-step explanation:
Step-by-step explanation:
T = time in seconds
H = distance
Tground = time to return to ground
Tmax = time at maximum height
H = -16T^2 + 672T...eqn 1
projectile returns to ground at H =0,
subs for H in eqn 1...
0 = -16T^2 + 672T
solving for T we get...
16T^2 = 672T
=> Tground = 42secs
Tmax = 0.5 Tground = 21secs
