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solmaris [256]
3 years ago
7

Can someone help with this Simplify: 9^-3

Mathematics
1 answer:
saw5 [17]3 years ago
6 0
Note that a^-3 = 1/a^3
9^3 = 729
1/9^3 = 1/729
Solution: 1/729
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Is the answer 200? Or 4.5??? Or is none ? I don't know it's confusing :/ can I get help :/
skelet666 [1.2K]
Let x = the number of penguins we are finding

x ÷ 100 × 30 = 15
x = 15 ÷ 30 × 100
x = 50

hope this helps and have a great day :)


6 0
3 years ago
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The slope of the graph is equal to
elena-s [515]

Answer:

what slope and graph? sorry!

8 0
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I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
Simplify.<br><br>1 – 2u + u + 4​
liq [111]

Answer:

-u+5

Step-by-step explanation:

plz mark as brainliest

5 0
3 years ago
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What is the value of x in the trangle? Enter your answer in the box. Round your final answer to the nearest hundredth.​
-Dominant- [34]

Use trigonometry.

cos(18°) = x/25

Multiply both sides by 25.

cos(18°)25 = x

23.7764129074 = x

We round off to the nearest hundredth. This means to round off to two decimal places.

Doing so, we get 23,78 cm = x.

4 0
4 years ago
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