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Galina-37 [17]
1 year ago
10

Find lim x->2 for f(x)=

Mathematics
1 answer:
TiliK225 [7]1 year ago
8 0

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

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Answer:

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Step-by-step explanation:

The equation is already in factored form.

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To solve the problem we must know about the Like terms and expressions.

<h3>What is an Expression?</h3>

In mathematics, an expression is a set of numbers, variables, and mathematical operations formed according to rules.

Given ;

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To  solve the algebraic expression,

3x(x - 12x) + 3x^2 - 2(x - 2)^2\\\\3x(x - 12x) + 3x^2 - 2(x^2 - 4x + 4)\\\\3x(x - 12x) + 3x^2 - 2x^2 + 8x - 8\\\\3x^2 - 36x^2 + 3x^2 - 2x^2 + 8x - 8\\\\-33x^2 + x^2 + 8x - 8\\\\\\-32x^2  + 8x - 8\\

To solve the problem we must know about the Like terms and expressions.

Learn more about Expression:

brainly.com/question/13947055

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