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Galina-37 [17]
2 years ago
10

Find lim x->2 for f(x)=

Mathematics
1 answer:
TiliK225 [7]2 years ago
8 0

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

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2 pts
34kurt

Answer:

67 and -1

Step-by-step explanation:

You always multiply first so its 7+64-4 and that becomes 67

You have to distribute first so the problem would be 5-21+15   which is -1

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4 years ago
What is 2 meters in centimeters??
fenix001 [56]

2 meters in centimeters would equal up to 200 centimeters. Meters and Centimeters are about 1 in the same. Centi meaning 100 is just a smaller measurement.

8 0
3 years ago
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Which expression is equivalent to (-1.3x - 4.5) -(-2. 1x + 3. 6)?
Reika [66]

Answer:

C) If im wrong im sorry

Step-by-step explanation:

5 0
3 years ago
Tre and Hector want to calculate the maximum possible throw at this field.
marissa [1.9K]

Answer:

d=455.38~units

Step-by-step explanation:

The coordinates of the dead center of the field, D\equiv (322,322)

Home base in a coordinate system is always the origin, O\equiv(0,0)

The center fielder threw the ball form the dead center to the home base, hence the distance of throw:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

d=\sqrt{(322-0)^2+(322-0)^2}

d=455.38~units

4 0
3 years ago
What is the average rate of change from -3 to 0<br>​
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