Well, 4 cups = 1 quart, so 4 *6= 24 cups in 6 quarts of lemonade.
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
d. I and III only
Step-by-step explanation:
I. The seeds should be randomly assigned to a treatment.
III. The number of successful seeds and unsuccessful seeds in each group should be at least 10.
The distribution of difference between two sample proportions :
Given :
Proportion 1 = P1 ;
Proportion 2 = P2 ;
Sample assignment for both samples 1 and 2 into the different treatment groups should be randomized, that is a simple random sampling of subjects into the treatment and control group. The sample design for difference between two sample proportions should be independent.
Finally each of the two proportions P1 and P2 should record a minimum of 10 successes and 10 non - successful Occurrences.
15.334 is the answer hope this helps
