T^2-t=12
t^2-t-12=0
(t-4)(t+3)=0
t=4, -3
<span>140% becomes 140/100. Since the GCF of these terms in the numerator and denominator is 20, divide each term by that value to get 7/5.</span>
x=1
i dont have an explaination
Hello!
We’ll begin by finding the number of periods in 1 hour. Using the given fact that each period is 1/3 of an hour, we can create and solve the following equation:
1 ÷
= 3
We have now proven that
there are 3 periods in every hour. We are now asked to find the number of periods in 8 hours. Using the fact that there are 3 periods to one hour, we can create and solve the following equation:
8 × 3 = 24
We have now proven that
there are 24 periods of time in 8 hours.
I hope this helps!
Actually Welcome to the Concept of the linear equation in two variables.
So we have to form two equations to solve this.
Let the number of children be 'x' and number of adults be 'y'.
hence, we get as,
x+y = 630 ..... (1)
and also, to their total cost spending, we get as,
1.5x + 2.25y = 1170 ...... (2)
solving (1) and (2) we get as,
Number of children were = 330
and Number of Adults were = 300
(Solved in the attachment)