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3 years ago

Swimming Pool On a certain hot summer's day, 630 people used the public swimming pool. The

Mathematics

1 answer:

crimeas [40]3 years ago

4 0

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the linear equation in two variables.

So we have to form two equations to solve this.

Let the number of children be 'x' and number of adults be 'y'.

hence, we get as,

x+y = 630 ..... (1)

and also, to their total cost spending, we get as,

1.5x + 2.25y = 1170 ...... (2)

solving (1) and (2) we get as,

Number of children were = 330

and Number of Adults were = 300

(Solved in the attachment)

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A spherical tank has a radius of 6 yards. It is filled with a liquid the cost $7.15 per cubic yard.

mote1985 [20]

We have two questions, but we need to find the volume of the spherical tank first.
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3 years ago

Read 2 more answers

Find the mode of the data set: 9 6 7 3 10 9

Phoenix [80]

Answer:

Step-by-step explanation:

Math definition Mode means anything that repeats more than anything else.

Eg.(4, 5, 6, 2, 2, 4, 4, 4, 4, 5, 3, 5)

The mode in the bracket is 4. Some of the numbers occured more than once but 4 occured the most that's why it's 4

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3 years ago

Plz help me, thank you

Kruka [31]

Answer:

$P=40(1.03526)^{t}$

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^{t}$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The initial number of bacteria is Po=40 and it doubles (P=2Po) at t=20 min. With that point we can find the value of r:

$2P_o=P_o(1+r)^{20}$

Simplifying:

$(1+r)^{20}=2$

Solving for 1+r:

$1+r=\sqrt[20]{2}$

$1+r=1.03526$

The exponential function that models the situation is:

$\mathbf{P=40(1.03526)^{t}}$

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3 years ago

The graph of f "(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is true?

kari74 [83]

Answer:

The graph of f has an inflection point at x = 0.

Step-by-step explanation:

An inflection point occurs when the second derivative changes signs. Since f"(x) is decreasing and has an x-intercept at 0, it changes signs from + to -, so there is an inflection point at x = 0.

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