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alexandr1967 [171]
2 years ago
14

Why is the MO structure of NO+ different than that of N2? (the structure, not the number of electrons)

Chemistry
1 answer:
Paladinen [302]2 years ago
5 0

N2 is a homonuclear molecule and NO+ is a heteronuclear molecular ion hence the  MO structure of NO+ different than that of N2.

<h3>What is the molecular orbital?</h3>

The molecular orbital is formed by the combination of atomic orbitals. We should note that the number of molecular orbitals must be equal to the number of combining atomic orbitals.

Now we know that N2 is a homonuclear molecule and NO+ is a heteronuclear molecular ion hence the  MO structure of NO+ different than that of N2.

Learn more about molecular orbital:brainly.com/question/13265432

#SPJ1

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If anyone could please help me i'd greatly appreciate it! I have tried over and over again and can not figure this out.
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%Ionization = 1.63%

Explanation:

Hydrazine in aqueous media theoretically forms a difunctional hydroxyl system. However, for this problem assume only monofunctional ionization occurs. A second hydroxyl ionization would not likely occur as the formal cationic charge formed in the 1st ionization would inhibit a second ionization.

H₂NNH₂ + 2H₂O => HONHNHOH => HONHNH⁺ + OH⁻; Kb = 1.3 x 10⁻⁶

So, assuming all OH⁻ and HONHNH⁺ are delivered in the 1st ionization then a good estimate of the %ionization can be calculated.

               HONHNHOH => HONHNH⁺  +  OH⁻

C(i) =>              0.490M                  0M           0M

ΔC =>                  -x                         +x             +x

C(eq) =>         0.490 - x                    x               x

                      ≅0.490M* => *x is dropped as Conc H₂NNH₂/Kb > 100

Kb = [HONHNH⁺][OH⁻]/[HONHNHOH]

1.3 x 10⁻⁶ = x²/0.490

=> x = [OH⁻] = [HONHNH⁺] = √[(1.3 x 10⁻⁶)(0.490)] = 8 x 10⁻⁴

=> %Ionization = (x/0.490)100% = (8 x 10⁻⁴/0.490)100% = 1.63%

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