Answer:
Mass of solvent is 1127.3 g
Explanation:
NaOCl → 3.62%
This percent means, that in 100 g of bleach solution, there are 3.62 g of NaOCl. So let's make a rule of three:
100 g of bleach solution have 3.62 g
1169.6 g of bleach solution may have (1169.6 . 3.62) /100 = 42.3 g
42.3 g is the mass of NaOCl in the solution
Mass of solution = Mass of solvent + Mass of solute
1169.6 g = Mass of solvent + 42.3 g
1169.6 g - 42.3 g = Mass of solvent → 1127.3 g
Your question can be found online! Just draw one of these diagrams
Answer:
1.15 M
Explanation:
Step 1: Given data
- Initial volume (V₁): 0.125 L
- Initial concentration (C₁): 3.00 M
- Final volume (V₂): 0.325 L
- Final concentration (C₂): ?
Step 2: Calculate the final concentration of the solution
We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M
Ion knoe Wdym by “be able to describ’ so ima put it in my own words idr lol:)
if you talm bout some kentic energy or sum ok but other Dan dat ion knoe tbh
I can explain how transferring kinetic energy in and out of a substance can cause a change
17.8 mL NaOH
<em>Step 1.</em> Write the chemical equation
Fe^(2+) + 2NaOH → Fe(OH)2 + 2Na^(+)
<em>Step 2.</em> Calculate the moles of Fe^(2+)
Moles of Fe^(2+) = 500 mL Fe^(2+) × [0.0230 mmol Fe^(2+)]/[1 mL Fe^(2+)]
= 11.50 mmol Fe^(2+)
<em>Step 3.</em> Calculate the moles of NaOH
Moles of NaOH = 11.50 mmol Fe^(2+) × [2 mmol NaOH]/[1 mmol Fe^(2+)]
= 23.00 mmol NaOH
<em>Step 4.</em> Calculate the volume of NaOH
Volume of NaOH = 23.00 mmol NaOH × (1 mL NaOH/1.29 mmol NaOH)
= 17.8 mL NaOH
