The distance between both lines is 2.24 units
Step-by-step explanation:
There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.
Given
We have to find the distance of this point from y=2x+5
The formula for finding distance of a point (x,y) from a line is:
A=2
B=-1
C=5
Putting the values in the formula
Rounding off will give: 2.24 units
The distance between both lines is 2.24 units
Keywords: Equations of lines
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Answer:
8 2/5 inches!
Step-by-step explanation:
The lighthouse is 120 feet, and 4 inches of height on the model equals 50 feet of height on the lighthouse. 100 divided by 50 = 2, and 4 multiplied by 2 is 8. 20 divided by 50 = 2/5, so the answer is 8 2/5 inches. :)
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
(-1,1.5) because you add both ys and both xs then divide by two to find the middle
There’s no picture so I’ll give my own answers.
The long side needs to be x radical 3, the short leg is just x, and the hypotenuse is 2x. So one example could be 5 radical 3, 5, and 5 times 2
