Answer:
<u>y = -x² + 4</u>
Step-by-step explanation:
The equation of the parabola in the vertex form is:
y = a (x-h)² + k
Where: (h,k) the coordinates of the vertex & a is a multiplier
The parabola has a vertex at ( 0,4 )
So, h = 0 , k = 4
∴ y = a (x-0)² + 4
∴ y = a x² + 4
The parabola passes through points ( 2,0 )
∴ 0 = a 2² + 4
∴ 4 a = -4 ⇒ a = -4/4 = -1
∴ y = -x² + 4
So, the equation of a parabola that has a vertex at ( 0,4 ) and passes through points ( 2,0 ) is <u>y = -x² + 4</u>
See the attached figure.
56.52 in^3
V(cylinder) = pi * r^2 * h
V = pi * 3^2 ^ 6
V = pi * 9 * 6
V = 54pi
V(sphere) = (4/3) * pi * r^3
V = (4/3) * pi * 3^3
V = (4/3) * pi * 27
V = 36pi
54pi - 36pi = 18 pi
18 * 3.14 = 56.52
Simple...
as far as I can see it looks like you need two names for the angle formed..-->>
the angle would be acute
and
complementary
Meaning both those angles <DHR and <DHM have to be both smaller than 90° but when you add them both they should equal 90°.
Thus, your answer.
-12,3 ...................................
Answer:
4√7-8
Step-by-step explanation:
