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alexandr1967 [171]
3 years ago
8

Tameron is driving 540 miles to college. If he drives at an average rate of 45 miles per hour, how many hours will it take him t

o get 3/4 of the way there?
Mathematics
1 answer:
zysi [14]3 years ago
4 0
Distance Tameron has to travel to reach college = 540 miles
Average speed at which Tameron drives = 45 miles per hour
It is required to find the number of hours it will take Tameron to drive upto 3/4th of the total distance to college. For this purpose we have to first find the 3/4 of the total distance.
Then
3/4 of the total distance to college = (3/4) * 540
                                                       = 3 * 135
                                                       = 405 miles.
Then
The time taken by Tameron to drive 405 miles = Distance traveled/Speed
                                                                           = 405/45
                                                                           = 9 hours.
So it will take Tameron 9 hours to drive 3/4 of the total distance to college.
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Step-by-step explanation:

I assume you mean ° (degrees), not ' (minutes).  There are 60 minutes in 1 degree.

S52°E means "south, 52° east", or 52° east of south.

S50°W means "south, 50° west", or 50° west of south.

1 knots = 1 nautical mile / hour, so the boat first travels 8 nautical miles from A to B, then 4.5 nautical miles from B to C, then finally back to A.

If we say A is at the origin, then the coordinates of B are:

(8 sin 52°, -8 cos 52°)

And the coordinates of C are:

(8 sin 52° − 4.5 sin 50°, -8 cos 52° − 4.5 cos 50°)

(2.857, -7.818)

So the distance from A to C is:

x = √(2.857² + (-7.818)²)

x ≈ 8.323

And the total distance of the race is:

d = 8 + 4.5 + 8.323

d = 20.823

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Here, the difference between the divisors and remainders is equal.

So, the required number is equal to LCM of (16,18,21)-6

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3 years ago
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How to <br> Write <br> 3/9<br> in simplest form.
White raven [17]
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