The triangular prism has 5 faces; two triangle faces and three rectangular faces.
We can find the area of one of the triangle faces by doing ((base * height) / 2). In this case, it would be ((2 * 2) / 2), which of course would equal 2"². Multiplied by two for the two triangles, which would be 4.
To find the area of one of the rectangles, we do (length * base), which would be (5 * 2) in our case, giving us 10. Multiply by 3 for the 3 faces, and we got 30"².
30 + 4 = 34"²
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
The second and third
Step-by-step explanation:
Answer:
$12
Step-by-step explanation:
We have to do this operation:
(16/4) x 3 = 4 x 3 = $12