Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):
second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:
Therefore runner B has the smaller period
11/12* (1/6)
= 11/72.
The final answer is 11/72~
Answer: The mechanic worked for 4.25 hours for the fourth customer.
First find out the slope.
Y^2-y^1/x^2-x^1
210-90/3-1=60
Slope: 60
Then find out what the y-intercept is by plugging in values we know into y=mx+b
90=60(1)+b
30=b
Y=60x+30
Substitute the y with 285 to find out the x (hours)
285=60x+30
4.25=x
Answer:
(9sqrt13)/13
Step-by-step explanation:
Answer:
<em>m</em> = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Slope Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points given from the graph.</em>
Point (0, 2)
Point (7, 2)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract:
- Divide:
Any horizontal line will have a slope of 0.
And we have our final answer!
