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White raven [17]
2 years ago
8

Durante una venta de liquidación, el Sr. Pablo, un profesor particular, compró un total de 12 libros de asesoría de Secundaria 4

y Secundaria 1 por S/82. El precio de un libro de asesoría de Secundaria 4 era de S/ 8 y el precio de un libro de asesoría de
Secundaria 1 era de S/ 6. Que el número de los libros de asesoría de Secundaria 1 comprados sea “k”.

a) Expresa el número de libros de asesoría de Secundaria 4 comprados en términos de “k”.

b) Forma una ecuación en “k' y resuélvela, calculando la cantidad de libros de cada tipo que compró el Sr.Pablo
Mathematics
1 answer:
Flauer [41]2 years ago
4 0

Resolviendo un sistema de ecuaciones, vemos que se venden 6 libros de secundaria 4 y 6 libros de secundaria 1.

<h3>¿Como escribir un sistema de ecuaciones?</h3>

Primero definimos dos variables:

  • x = numero de libros de secundaria 4 vendidos.
  • k = número de libros de secundaria 1 vendidos.

Sabemos que se venden 12 libros en total, entonces:

x + k = 12

Tambien sabemos que se recauda un total de $82, entonces:

x*$8 + k*$6 = $82

Entonces tenemos dos ecuaciones.

a) Usando la primer ecuacion, podemos aislar x para tener:

x = 12 - k

b) Ahora podemos reemplazar eso en la otra ecuación para solucionar el sistema.

(12 - k)*$8 + k*$6 = $82

$96 - $2*x = $82

$2*x = $12

x = $12/$2 = 6

Es decir se venden 6 libros de secundaria 4, y como se venden 12 libros en total, los otros 6 libros vendidos son de secundaria 1.

Si quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

#SPJ1

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Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan
Lunna [17]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 41  

    Alternate Hypothesis, H_A : \mu > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let \mu = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, H_0 : \mu \leq 41     {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean = 47

            σ = population standard deviation = 35

            n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em>  =  \frac{47-41}{\frac{35}{\sqrt{40} } }

                                      =  1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

                P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

                              = 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0
4 years ago
-(-4)(-6)-3/5(10+15)/1/3
Ksenya-84 [330]

Answer:

-29

solving steps:

\sf \hookrightarrow -\left(-4\right)\left(-6\right)-3/5\left(10+15\right)/1/3

\sf \hookrightarrow  -\left(-4\right)\left(-6\right)-3/5\cdot \:25/1/3

\sf \hookrightarrow  -24-3/5\cdot \:25/1/3

\sf \hookrightarrow  -24-5

\sf \hookrightarrow  -29

3 0
2 years ago
Read 2 more answers
Pls answer quick it's gr 9 academic math lol
SVETLANKA909090 [29]

Answer:

1. (3^3 + 3^2)^2 actually equals (27 + 9)^2

which is the first mistake

2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7

3. 3^7 DOES NOT EQUAL 21

Step-by-step explanation:

when you add powered numbers together, it does not multiply it, as your example:

1. (3^3 + 3^2)^2 actually equals (27 + 9)^2

which is the first mistake

2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7

3. 3^7 DOES NOT EQUAL 21

4 0
3 years ago
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I ordered some books online for myself and friends. ​Each book costs \$ 13$13 and the store charges a flat rate for shipping of
Sonbull [250]

Answer: 13n + 20

Step-by-step explanation:

The cost of each book is $13. That means that if you end up buying "n" books, cost would be:

= Cost of each book * number of books

= 13 * n

= 13n

You would also get charged a flat rate for shipping of $20 which would be added to the above cost to bring a total of:

= 13n + 20

8 0
3 years ago
Is Y=3x linear or non linear?
stealth61 [152]

Answer:

linear

Step-by-step explanation:

8 0
3 years ago
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